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Neporo4naja [7]
4 years ago
7

What is 6.25 divided by 5?

Mathematics
2 answers:
Tpy6a [65]4 years ago
8 0

Answer:

1.25

Step-by-step explanation:

6.25 divided by 5 = 1.25

garik1379 [7]4 years ago
5 0

Answer: 1.25

Step-by-step explanation:

6.25/5=1.25

Hope this helps!

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Please help me thanks
KiRa [710]

Answer:

1,2,4,5,10

1,2,3,5,6

60

Step-by-step explanation:

7 0
3 years ago
Find the ratio that is equivalent to 10:5.<br> OA) 15:5<br> OB) 5:10<br> OC) 2:1<br> OD 5:1
Vesnalui [34]

Answer:

OB) 2:1

Step-by-step explanation:

5 can go into 10 twice and 5 can go into itself once

6 0
3 years ago
Read 2 more answers
If it requires 6 pounds of wild caught animals to create 1 pound of salmon, what percent of the wild caught animals are wasted?
Oduvanchick [21]

The percentage of animal wasted is the number of animal wasted over 100

85.7%  of the wild caught animals are wasted

<h3>How to calculate the animal wasted</h3>

From the question, we have:

Animals caught = 6 pounds

Salmon = 1 pound

The total weight in the system is:

Total = 6 pounds + 1 pound

So, we have:

Total = 7 pounds

The percent of wild caught animals wasted is then calculated as:

\%Wasted = \frac{6}{7} * 100\%

Simplify

\%Wasted = 85.7\%

Hence, 85.7%  of the wild caught animals are wasted

Read more about percentage at:

brainly.com/question/843074

4 0
2 years ago
Find the slope of the line that passes through (4, 18) and (7, 10).
hichkok12 [17]

The right answer is -8/3

please see the attached picture for full solution

hope it helps

3 0
3 years ago
Read 2 more answers
A resident of Bayport claims to the City Council that the proportion of Westside residents
Kazeer [188]

Answer:

The test statistics is  z =  -1.56  

The p-value is   p-value =  0.05938

Step-by-step explanation:

From the question we are told  

   The West side sample  size is n_1  =  578

    The  number of residents on the West side with income below poverty level is k  = 76

    The East side sample size  n_2=688

  The  number of residents on the East side with income below poverty level is u  = 112

   The null hypothesis is  H_o  :  p_1 = p_2

    The alternative hypothesis is  H_a :  p_1 <  p_2

Generally the sample proportion of  West side is  

     \^{p} _1 = \frac{k}{n_1}

=>   \^{p} _1 = \frac{76}{578}

=>   \^{p} _1 =  0.1315

Generally the sample proportion of  West side is  

     \^{p} _2 = \frac{u}{n_2}

=>   \^{p} _2 = \frac{112}{688}

=>   \^{p} _2 =  0.1628

 Generally the pooled sample proportion is mathematically represented as

    p = \frac{k + u}{ n_1 + n_2 }

=>  p = \frac{76 + 112}{ 578 + 688 }

=>  p =0.1485

Generally the test statistics is mathematically represented as

z = \frac{\^ {p}_1 - \^{p}_2}{\sqrt{p(1- p) [\frac{1}{n_1 } + \frac{1}{n_2}  ]}  }

=> z = \frac{ 0.1315  - 0.1628 }{\sqrt{0.1485(1-0.1485) [\frac{1}{578} + \frac{1}{688}  ]}  }  

=> z =  -1.56  

Generally the p-value  is mathematically represented as

          p-value =  P(z <  -1.56 )

From z-table  

         P(z <  -1.56 ) =  0.05938

So

     p-value =  0.05938

3 0
4 years ago
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