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pantera1 [17]
4 years ago
7

What value of a makes this equation true?

Mathematics
2 answers:
Goshia [24]4 years ago
7 0

9/10=a/30. and value of a is 27

sergeinik [125]4 years ago
4 0

Answer:

27

Step-by-step explanation:

We can use cross products to solve

9          a

----- = --------

10        30

9*30 = 10a

270 = 10a

Divide each side by 10

270/10 = 10a/10

27 =a

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Prove the trigonometric identity
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Answer:

Proved See below

Step-by-step explanation:

Man this one is a world of its own :D Just a quick question are you a fellow Add Math student in O levels i remember this question from back in the day :D Anyhow Lets get started

For this question we need to know the following identities:

1+tan^{2}x=sec^2x\\\\1+cot^2x=cosec^2x\\\\sin^2x+cos^2x=1

Lets solve the bottom most part first:

1-\frac{1}{1-sec^2x} \\\\

Take LCM

1-\frac{1}{1-sec^2x} \\\\\frac{1-sec^2x-1}{1-sec^2x} \\\\\frac{-sec^2x}{1-sec^2x} \\\\\frac{-(1+tan^2x)}{-tan^2x}

now break the LCM

\frac{-1}{-tan^2x}+\frac{-tan^2x}{-tan^2x}\\\\\frac{1}{tan^2x}+1\\\\cot^2x+1

because 1/tan = cot x

and furthermore,

cot^2x+1\\cosec^2x

now we solve the above part and replace the bottom most part that we solved with cosec^2x

\frac{1}{1-\frac{1}{cosec^2x} } \\\\\frac{1}{1-sin^2x} \\\\\frac{1}{cos^2x}\\\\sec^2x

Hence proved! :D

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3 years ago
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umka21 [38]

<em>Note: Your answer choices remain a little unclear. But, I have solved the concept and solution, so you can easily figure it out.</em>

Answer:

\left(-7x^0+5x^2-x+6\right)-\left(-8x^2+x+3\right)=13x^2-2x-4

Step-by-step explanation:

Given the expression

\left(-7x^0+5x^2-x+6\right)-\left(-8x^2+x+3\right)

solving the expression

=-7x^0+5x^2-x+6-\left(-8x^2+x+3\right)

apply the rule: a^0=1,\:a\ne \:0

=-7+5x^2-x+6-\left(-8x^2+x+3\right)

=-7+5x^2-x+6+8x^2-x-3

simplify

=13x^2-2x-4

Therefore, the simplified form is:

\left(-7x^0+5x^2-x+6\right)-\left(-8x^2+x+3\right)=13x^2-2x-4

<em>Note: Your answer choices remain a little unclear. But, I have solved the concept and solution, so you can easily figure it out.</em>

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The answer to your question is 43
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