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Margarita [4]
3 years ago
14

Which statement is true about the end behavior of the function represented by the graph?

Mathematics
1 answer:
Zepler [3.9K]3 years ago
7 0

End behavior always involves x approaching positive and negative infinity. So we'll cross off the choice that says "x approaches 1".

The graphs shows both endpoints going down forever. So both endpoints are going to negative infinity regardless if x goes to either infinity.

<h3>Answer: Choice B</h3><h3>As x approaches −∞, f(x) approaches −∞, and as x approaches ∞, f(x) approaches −∞.</h3>

Another way to phrase this would be to say "f(x) approaches negative infinity when x goes to either positive or negative infinity"

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Answer:

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Please help me i'll mark Brainliest!!!
ololo11 [35]

<u><em>4^(1/7) = ⁷√(4)</em></u>

<u><em>4^(7/2) = √(4)^7</em></u>

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<u><em>7^(1/2) =  √(7)</em></u>

I believe this is it...

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3 years ago
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jekas [21]

16:30

16/30

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1 2.2.5 Quiz: Volume
LUCKY_DIMON [66]

Answer:

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3 years ago
Part of the proceeds from a garage sale was $455 worth of $5 bills and $20 bills. If there were 6 more $5 bills than 20$ bills f
Feliz [49]

Answer:

\large \boxed{\text{17 \$20 bills and 23 \$5 bills}}

Step-by-step explanation:

               Let x = the number of $20 bills.

     Then x + 6 = the number of $5 bills  and

20x + 5(x +  6) = 455

\begin{array}{rcl}20x + 5(x + 6) & = & 455\\20x + 5x + 30 & = & 455\\25x + 30 & = & 455\\25x & = & 425\\x & = &\dfrac{425}{25}\\\\x & = &\mathbf{17}\\\end{array}

                    x = 17 = number of $20 bills

x + 6 = 17 + 6 = 23 = number of $5 bills

\text{There were }\large \boxed{\textbf{17 \$20 bills and 23 \$5 bills}}

Check:

\begin{array}{rcl}20\times17+ 5(17 + 6) & = & 455\\340 + 5\times23& = & 455\\340 + 115 & = & 455\\455 & = & 455\\\end{array}

OK.

7 0
3 years ago
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