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postnew [5]
3 years ago
7

What is the width of a rectangle with length 14cm and area 161 cm^2

Mathematics
2 answers:
MrMuchimi3 years ago
8 0

Answer:

11.5 cm

Step-by-step explanation:

width \: of \: rectangle \\  \\  =  \frac{area \: of \: rectangle}{length \: of \: rectangle}  \\  \\  =  \frac{161}{14} \\  \\  =  11.5 \: cm

Inessa05 [86]3 years ago
3 0

Answer:

Step-by-step explanation:

The area of a rectangle can be found with the formula A = l*w, where l is the length of the rectangle and w is the width.

From the given problem statement, we know that l = 14 and A = 161, so we can fill in those values in the formula anbd solve for w to get the width:

A = l*w

161 = 14w

Divide both sides by 14 to isolate w by itself:

\frac{161}{14} = \frac{14w}{14}

w = 11.5

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so she spent 240 minutes on a 3 minute video
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A certain recipe requires 415 cups of flour and 237 cups of sugar. a) If 49 of the recipe is to be made, how much sugar is neede
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Listed below is the amount of commissions earned last month for the eight members of the sales staff at Best Electronics. Calcul
Solnce55 [7]

Answer:

0.438

Step-by-step explanation:

Given the data:

980.9, 1036.5, 1099.5, 1153.9, 1409.0, 1456.4, 1718.4, 1721.2

Coefficient of skewness:

3 * (mean - median) / standard deviation

The mean of the dataset :

Σ(X) / N ; N = sample size = 8

980.9+1036.5+1099.5+1153.9+1409.0+1456.4+1718.4+1721.2

= 10575.8 / 8

= 1321.975

Median :

980.9, 1036.5, 1099.5, 1153.9, 1409.0, 1456.4, 1718.4, 1721.2

1/2(n + 1)th term

1/2(9) = 4.5th term

(1153.9+1409.0) / 2

= 1281.45

Standard deviation:

Sqrt[Σ(X - mean)²/ (N - 1)]

Using calculator :

Standard deviation estimate of population = 277.882456

Coefficient of skewness :

3(1321.975 - 1281.45) / 277.882456

121.575 / 277.882456

= 0.4375051

= 0.4375

Using software excel :

Using excel's AVERAGE, MEDIAN and STDEV.P functions, the Coefficient of skewness can be obtained using the formula :

3 * (mean - median) / standard deviation

Coefficient of skewness obtained is 0.438

8 0
3 years ago
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