Hey there. So basically, find out how much the pencils and notebooks cost first.
The notebooks cost = $3.25
The pencils cost = $0.50
Then, think about what you need to figure out in this problem.
Jake has $20. You need to find how many notebooks Jake can buy in maximum after buying 8 pencils.
If Jake buys 8 pencils that costs $0.50 each, he spends $4 on the pencils.
So now, to find out how many notebooks he can buy, do 20 minus 4.
Jake's got $16 left.
If the notebooks cost $3.25 each, we need to find out how many notebooks he can buy by dividing them. So, 16 divided by 3.25 equals 4.923... and so on.
That means, Jake can buy 4 notebooks with his remaining money.
Answer:
x=2
Step-by-step explanation:
2x+10=14
2x=14-10
2x=4
x=4/2
x=2
Mom's view is that she loses 50 dollars, but gains back 17.85 dollars as change from her daughter.
Olivia's view is that she gained 50 dollars from her mom, spent 32.15 dollars, then gave back the 17.85 change to her mom, so she didn't gain any money.
Mom's point of view: -$50 + $17.85 and Mom's point of view: -$50 + $17.85 are the correct answers, but technically, Olivia still owes her mom 32.15 dollars.
Answer:
First, we need to find the amount of dip that was divided amount the two friends.
We know that it is 4/7 of the left dip
therefore:
amount divided among the two friends = (4/7) x (3/4) = 3/7 of the original amount of dip.
This amount is divided among two friends,
therefore:
amount that each friend gets = (3/7) / (2) = 3/14 = 0.2 of the amount of dip
tell me if this is completely wrong because i'm not good at this
Answer:
What is P(A), the probability that the first student is a girl? (3/4)
What is P(A), the probability that the first student is a girl? (3/4)What is P(B), the probability that the second student is a girl? (3/4)
What is P(A), the probability that the first student is a girl? (3/4)What is P(B), the probability that the second student is a girl? (3/4)What is P(A and B), the probability that the first student is a girl and the second student is a girl? (1/2)
The probability that the first student is a girl is (3/4), likewise for the 2nd 3rd and 4th it's still (3/4). The order you pick them doesn't matter.
However, once you're looking at P(A and B) then you're fixing the first position and saying if the first student is a girl what's the probability of the second student being a girl.
