Answer:
Quadratic Formula x = [-b +- Sq root (b^2 - 4ac)] / 2a
In this example a= 2 b= -6 c= 5
x = [- - 6 +- Sq root ((-6^2) - 4 *2*5)] / 2*2
x = [6 +-sq root (36 -40)] / 4
x = 6 +- 2i / 4
x1 = 1.5 + .5i
x2 = 1.5 -.5i
Step-by-step explanation:
Answer:
Look Down
Step-by-step explanation:
7) D
8) B
9) A
10) B
11) C
12) D
13) A
14) B
Answer:
! means factorial . For example 3! (factorial 3) = 3*2*1 = 6
Answer to 14C3 is 364
Step-by-step explanation:
14! = 14*13*12*11*10*9*8*7*6*5*4*3*2*1
14C3 = 14*13*12*11*10*9*8*7*6*5*4*3*2*1 / 3*2*1 * 11*10*9*8*7*6*5*4*3*2*1
= (14*13*12) / 3*2*1
= 14*13*2
= 364
9x^2-11y^2-11x
that is the sum of the polynomials
Answer:
Step-by-step explanation:
The base case in the recursive function are:
The recursive case is equal to:
So replace for :
In the new expression is a base case so you don't have to worry for that part, but is still the recursive case so evaluate again in
and are define as base cases so you replace for it's numbers:
Now return to and replace for the new values:
So the final answer is 20