Find two odd consecutive nmbers whose sum is 300

Mathematics

1 answer:

IRISSAK [1]2 years ago

4 0

Answer:

149 and 151

just split the number in half then add one to the first number the subtract one from the second number

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a) Suppose you are able to download 1 free song to your tablet daily and each additional download costs $0.59. If your monthly b

icang [17]

If 1 additional song costs $0.59, then there would be 26 additional songs downloaded. Because $15.34 divided by $0.59 is 26.

Let x be the number of songs downloaded.

x = 28 + (15.34/0.59)
x = 28 + (26)
x = 54

You have 54 songs downloaded on your tablet.

Hope this helps :)

7 0

3 years ago

Find mHK.<br> pls hurry and answer lol

Rashid [163]

It would be mark N? I think

7 0

3 years ago

Read 2 more answers

Six times a number is 45 greater than the product of the number and -3. Find the number.

LiRa [457]

Answer:

Step-by-step explanation:

6a = (a*-3) + 45

then:

6a = -3a + 45

6a + 3a = 45

9a = 45

a = 45/9

a = 5

Check:

6*5 = (5*-3) + 45

30 = -15 + 45

8 0

2 years ago

A box contains 3 coins. One coin has 2 heads and the other two are fair. A coin is chosen at random from the box and flipped. If

Blababa [14]

Answer: Our required probability is $\dfrac{1}{2}$

Step-by-step explanation:

Since we have given that

Number of coins = 3

Number of coin has 2 heads = 1

Number of fair coins = 2

Probability of getting one of the coin among 3 = $\dfrac{1}{3}$

So, Probability of getting head from fair coin = $\dfrac{1}{2}$

Probability of getting head from baised coin = 1

Using "Bayes theorem" we will find the probability that it is the two headed coin is given by

$\dfrac{\dfrac{1}{3}\times 1}{\dfrac{1}{3}\times \dfrac{1}{2}+\dfrac{1}{3}\times \dfrac{1}{2}+\dfrac{1}{3}\times 1}\\\\=\dfrac{\dfrac{1}{3}}{\dfrac{1}{6}+\dfrac{1}{6}+\dfrac{1}{3}}\\\\=\dfrac{\dfrac{1}{3}}{\dfrac{2}{3}}\\\\=\dfrac{1}{2}$