<u>ANSWER</u>
A. (4,12)
<u>EXPLANATION</u>
The equations are:
and
To eliminate a variable we make the coefficients of that variable the same in both equations.
It is easier to eliminate x.
We multiply the first equation by 2 to get:
We add equations (2) and (3).
Divide both sides by 23
Put x=4 into equation (1).
The solution is (4,12)
I assume there are some plus signs that aren't rendering for some reason, so that the plane should be
.
You're minimizing
subject to the constraint
. Note that
and
attain their extrema at the same values of
, so we'll be working with the squared distance to avoid working out some slightly more complicated partial derivatives later.
The Lagrangian is
Take your partial derivatives and set them equal to 0:
Adding the first three equations together yields
and plugging this into the first three equations, you find a critical point at
.
The squared distance is then
, which means the shortest distance must be
.
Answer:
i√19
Step-by-step explanation:
Because √(-19) = √(-1)√19, and because √(-1) = i, we get i√19
49/9=m/n this is because you multiply by the reciprocal of 3/7
