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marysya [2.9K]
3 years ago
12

QUESTION 20

Mathematics
1 answer:
atroni [7]3 years ago
7 0

.Answer:

The answer is below

Step-by-step explanation:

The patient loses 1 kg every week for 5 weeks.

1 kg = 2.2 lbs

Therefore the patient loses 2.2 lbs every week for 5 weeks.

a) The weight of the patient after 5 weeks = 245 lbs. - (5 weeks)(2.2 lbs per week)

The weight of the patient after 5 weeks = 245 lbs. - 11 lbs. = 234 lbs.

b) The weight of the patient after 5 weeks = 245 lbs. - 11 lbs. = 234 lbs.

1 kg = 2.2 lbs.

234 lbs. = 234 lbs. * 1 kg per 2.2 lbs. = 106.36 kg

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7/18 times 3 in simplest form
IRISSAK [1]

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21/18 which simplifies to <u>7/6</u>

Step-by-step explanation:

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Find the measure of the indicated angle to the nearest degree
Alisiya [41]

Answer:

The answer to your question is below

Step-by-step explanation:

14) sin Ф = 32/33

    sin Ф = 0.9697

        Ф = 75.86°

15) sin Ф = 16/36

     sin Ф = 0.444

          Ф = 26.39°

16) sin Ф = 29/36

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          Ф = 53.66°

17) cos Ф = 11/34

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18) sin Ф = 21/40

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           Ф = 31.67°

19) cos Ф = 6/14

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20) cos Ф = 38/39

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3 0
3 years ago
Alicia says that 6 ÷ 2 + 5 is the same as 5 + 6 ÷ 2. Is Alicia correct or incorrect? Explain.
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Answer:

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Step-by-step explanation:

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4 0
3 years ago
Read 2 more answers
4. a) A ping pong ball has a 75% rebound ratio. When you drop it from a height of k feet, it bounces and bounces endlessly. If t
Klio2033 [76]

First part of question:

Find the general term that represents the situation in terms of k.

The general term for geometric series is:

a_{n}=a_{1}r^{n-1}

a_{1} = the first term of the series

r = the geometric ratio

a_{1} would represent the height at which the ball is first dropped. Therefore:

a_{1} = k

We also know that the ball has a rebound ratio of 75%, meaning that the ball only bounces 75% of its original height every time it bounces. This appears to be our geometric ratio. Therefore:

r=\frac{3}{4}

Our general term would be:

a_{n}=a_{1}r^{n-1}

a_{n}=k(\frac{3}{4}) ^{n-1}

Second part of question:

If the ball dropped from a height of 235ft, determine the highest height achieved by the ball after six bounces.

k represents the initial height:

k = 235\ ft

n represents the number of times the ball bounces:

n = 6

Plugging this back into our general term of the geometric series:

a_{n}=k(\frac{3}{4}) ^{n-1}

a_{n}=235(\frac{3}{4}) ^{6-1}

a_{n}=235(\frac{3}{4}) ^{5}

a_{n}=55.8\ ft

a_{n} represents the highest height of the ball after 6 bounces.

Third part of question:

If the ball dropped from a height of 235ft, find the total distance traveled by the ball when it strikes the ground for the 12th time. ​

This would be easier to solve if we have a general term for the <em>sum </em>of a geometric series, which is:

S_{n}=\frac{a_{1}(1-r^{n})}{1-r}

We already know these variables:

a_{1}= k = 235\ ft

r=\frac{3}{4}

n = 12

Therefore:

S_{n}=\frac{(235)(1-\frac{3}{4} ^{12})}{1-\frac{3}{4} }

S_{n}=\frac{(235)(1-\frac{3}{4} ^{12})}{\frac{1}{4} }

S_{n}=(4)(235)(1-\frac{3}{4} ^{12})

S_{n}=910.22\ ft

8 0
2 years ago
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