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Vitek1552 [10]
4 years ago
11

Explain how you get the answer to 7|8-3h|=21h-49

Mathematics
1 answer:
DerKrebs [107]4 years ago
8 0

Awnser-H=5/2

Explantion- Absolute value equalitiy entered

     7|-3h+8| = 21h-49  Clear the absolute-value bars by splitting the equation into its two cases, one for the Positive case and the other for the Negative case.

The Absolute Value term is 7|-3h+8|

For the Negative case we'll use -7(-3h+8)  

For the Positive case we'll use 7(-3h+8)  

-7(-3h+8) = 21h-49  

    Multiply

     21h-56 = 21h-49  

    Rearrange and Add up

     0h = 7  

    False, No solution for the Negative Case 7(-3h+8) = 21h-49  

    Multiply

     -21h+56 = 21h-49  

    Rearrange and Add up

     -42h = -105  

    Divide both sides by 42

     -h = -(5/2)  

    Multiply both sides by (-1)

     h = (5/2)  

    Which is the solution for the Positive Case When an absolute value equation has just one solution, that solution has to be checked:

The equality is  7|-3h+8| = 21h-49  

The solution is  h = 5/2  

We check the solution by plugging it for h

7|-3(5/2)+8| = 21(5/2)-49  

The left hand side is equal to   (7/2)  

The right hand side is equal to   (7/2)  

The two sides are equal!

Solution checks!

h=5/2

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the circumference of the circle= 36pi units  

Step-by-step explanation:


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The temperature fell from 0 degrees to 15 1/2 degrees below 0 in 5 3/4 hours. Wen tried to find the change in temperature per ho
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-62/23 degrees per hour

Step-by-step explanation:

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3 0
3 years ago
A Geiger counter counts the number of alpha particles from radioactive material. Over a long period of time, an average of 14 pa
UkoKoshka [18]

Answer:

0.2081 = 20.81% probability that at least one particle arrives in a particular one second period.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Over a long period of time, an average of 14 particles per minute occurs. Assume the arrival of particles at the counter follows a Poisson distribution. Find the probability that at least one particle arrives in a particular one second period.

Each minute has 60 seconds, so \mu = \frac{14}{60} = 0.2333

Either no particle arrives, or at least one does. The sum of the probabilities of these events is decimal 1. So

P(X = 0) + P(X \geq 1) = 1

We want P(X \geq 1). So

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-0.2333}*(0.2333)^{0}}{(0)!} = 0.7919

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.7919 = 0.2081

0.2081 = 20.81% probability that at least one particle arrives in a particular one second period.

8 0
4 years ago
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