1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ludmilkaskok [199]
3 years ago
7

On average, it takes a shoe factory 21 minutes, with a standard deviation of 3 minutes, to manufacture a pair of running shoes.

How often will it take the factory more than 27 minutes to manufacture a pair of running shoes?
Mathematics
1 answer:
algol133 years ago
7 0

Answer:

The number of times it would take more than 27 minutes to manufacture a pair of running shoes is 2.275 times or approximately 2 times per every 100 shoes

Step-by-step explanation:

The average time it takes to manufacture a pair of shoes = 21 minutes;

The standard deviation = 3 minutes

To find how often it takes more than 27 minutes to manufacture a pair of running shoes, we have;

Standard score, given as follows;

Z=\dfrac{x-\mu }{\sigma }

Where;

x = The raw score = 27 minutes

μ = The average score = 21 minutes

σ = The standard deviation = 3 minutes

From which we have;

Z=\dfrac{27-21 }{3 } = 2

Therefore, it is borderline unusual with a p value of P(z>2) = 1 - 0.97725 = 0.02275

Therefore, the number of times out of 100 that it would take more than 27 minutes to manufacture a pair of running shoes = 100 × 0.02275 = 2.275 times which is approximately 2 times in every 100 shoes.

You might be interested in
Consider the figure below. Abraham cut regular pentagon ABCDE into quadrilateral BEGC. Which of the following statements is true
Genrish500 [490]

Let 'n' be the number of side of a regular polygon each angle are equal and sum of  each angle equal to (n-2)×180. \\∴For a regular pentagon have five equal side, n=5\\ ∴ sum of each angle = (n-2)×180=3×180 = 540. and ecah angle = 540÷5=108°. Therefore ∠BCG = 108° and ∠ABC =108° \\ Here BE is one of the diagonal of regular pentagon ABCDE. BE divide ∠ABC in 1:2 ratio \\ Therefore ∠ABE : ∠CBE = 36: 72\\∴ ∠GCB + ∠CBE = 108° +72°=180°

5 0
3 years ago
Read 2 more answers
A rectangle is 19 feet long and 42 feet wide. What is the area of the rectangle, in square yards? Express your answer as a mixed
Temka [501]

Answer:

86\frac{2}{3} yards²

Step-by-step explanation:

19 feet = \frac{19}{3} yards

42 feet = 14 yards

14 × \frac{19}{3} = \frac{266}{3} = 86\frac{2}{3}

4 0
3 years ago
Solve equation for the specified variable<br> dx +t=10 , solve for x
slamgirl [31]
Dx+t=10
    -t     -t
dx=10-t
÷d      ÷d
x=(10-t)/d
4 0
3 years ago
Cláudio pode ir de sua casa a escola andando três km para o Norte, 2 para o oeste, um para o sul, quatro para o leste e, finalme
VARVARA [1.3K]

Answer:

b) 2 Km para o leste

Step-by-step explanation:

1. 2 km N

2. 2 km W

3. 1 km S

4. 4 km E

5. 2 km S

Sul e Norte:

(1.) 2 km N + (3.) 1 km S + (5.) 2 km S = 2 km - 1 km - 2 km = 0

Este e Oeste:

(2.) 2 km W + (4.) 4 km E = -2 km + 4 km = 2 km E

Veja imagem abaixo.

7 0
2 years ago
108 divided by 9 using distributive property
Lostsunrise [7]

108 = 81 + 27

Step 1: 81 / 9 = 9

Step 2: 27 / 9 = 3

Step 3: 3 + 9 = 12

108 / 9 = 12

Hope this helps! :D

7 0
3 years ago
Other questions:
  • What are clouds circling the “eye” called
    6·1 answer
  • If x = 4y + 21y and y = 14 + 5, what is 3x × 7? No need to show your work.
    12·2 answers
  • Find percent notation<br> 0.488
    14·1 answer
  • Need help with this
    10·2 answers
  • How would I go about solving this?
    9·1 answer
  • Billy walks 15 miles every day to soccer practice, and catches a ride home from his grandma. Billy had 5 practices last week. Ho
    12·1 answer
  • What value of x makes x/20 and 3/4 proportionate
    10·2 answers
  • Find the lateral area of the right triangular prism below.<br> 5 in, 12 in, 13 in
    7·1 answer
  • 1.11(5) - 11(4) =
    6·1 answer
  • QUESTION 11 1 POINT
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!