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Brums [2.3K]
3 years ago
15

Which values are solutions to 90 < –30p + 15? check all that apply.p = –10p = 0p = –2.5p = 3p = –5p = 7.6?

Mathematics
1 answer:
Paha777 [63]3 years ago
7 0

The given inequality is

90 < -30p + 15

We need to isolate p, and for that , first we subtract 15 to both sides, that is

90-15< -30p+15-15

75 < -30p

Dividing both sides by -30. And on dividing by negative number, the sign of the inequality change . That is

-2.5>p&#10;\\&#10;p

And -10 is less then -2.5 . So the correct option is

p=-10

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Step-by-step explanation:

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The correct question is
<span>A student ate 3/20 of all candies and another 1.2 lb. Another student ate 3/5 of the candies and the remaining 0.3 lb. Altogether, what weight of candies did they eat?</span>

let
x-------> total <span>weight of candies
we know that

x=(3/20)*x+1.2+(3/5)*x+0.3
</span>x=(3/20)*x+(3/5)*x+1.5----> multiply by 20----> 20x=3x+12x+30
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3 years ago
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3 years ago
A card is selected randomly from a jar that contains 15 cards, numbered from 25 to 39. What is the probability that the card sel
VikaD [51]

Answer:

The probability that the card selected bears a number less than 34 is 0.3333.

Step-by-step explanation:

Let random variable <em>X</em> be defined as the number on the selected card.

There are <em>N</em> = 15 total cards.

The number on the cards are as follows:

S = {25, 26, 27,..., 38, 39}

The probability of an event, <em>E</em> is the ratio of the number of favorable outcomes to the total number of outcomes.

P(E)=\frac{n(E)}{N}

In this case we need to compute the probability that the card selected bears a number less than 34.

The favorable outcomes are:

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Compute the probability that the card selected bears a number less than 34 as follows:

P(X

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Answer:

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