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EastWind [94]
3 years ago
11

Given: 5n-42=12n prove: n=-6

Mathematics
2 answers:
Leviafan [203]3 years ago
6 0

Answer:

5n-42=12n

5n-42+42=12n+42

5n=12n+42

5n-12n=12n+42-12n

-7n=42

-7n/-7 = 42/-7

n= -6

Vikentia [17]3 years ago
3 0

Answer:

n=-6

Step-by-step explanation:

5n-42=12n

5n=12n+24

5n-12n=42

-7n=42

divide each side by -7

n does =-6

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The Are 20 Empty Seats
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3 years ago
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What is the solution to this system of equations?
Ede4ka [16]

Answer:

First choice.

Step-by-step explanation:

You could plug in the choices to see which would make all the 3 equations true.

Let's start with (x=2,y=-6,z=1):

2x+y-z=-3

2(2)+-6-1=-3

4-6-1=-3

-2-1=-3

-3=-3 is true so the first choice satisfies the first equation.

5x-2y+2z=24

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10+12+2=24

24=24 is true so the first choice satisfies the second equation.

3x-z=5

3(2)-1=5

6-1=5

5=5 is true so the first choice satisfies the third equation.

We don't have to go any further since we found the solution.

---------Another way.

Multiply the first equation by 2 and add equation 1 and equation 2  together.

2(2x+y-z=-3)

4x+2y-2z=-6 is the first equation multiplied by 2.

5x-2y+2z=24

----------------------Add the equations together:

9x+0+0=18

9x=18

Divide both sides by 9:

x=18/9

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Using the third equation along with x=2 we can find z.

3x-z=5 with x=2:

3(2)-z=5

6-z=5

Add z on both sides:

6=5+z

Subtract 5 on both sides:

1=z

Now using the first equation along with 2x+y-z=-3 with x=2 and z=1:

2(2)+y-1=-3

4+y-1=-3

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Subtract 3 on both sides:

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So the solution is (x=2,y=-6,z=1).

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Answer:

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3 years ago
I have no idea how to do this.
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