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lyudmila [28]
3 years ago
7

Q varies inversely as the square of p, and Q = 36 when p = 7. Find Q when p = 6.

Mathematics
1 answer:
snow_lady [41]3 years ago
4 0

Answer:

49

Step-by-step explanation:

1. Calculate the constant of proportionality

Q = k/p²

k = Qp²     Multiplied each side by p²

  = 36 × 7²

  = 36 × 49

  = 1764

2. Calculate the new value of Q

Q = 1764/p²

  = 1764/36

Q = 49

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To find:

The zeros of the given function.

Solution:

The general form of polynomial is

P(x)=a(x-c_1)^{m_1}(x-c_2)^{m_2}...(x-c_n)^{m_n}       ...(i)

where, a is a constant, c_1,c_2,...,c_n are zeros of respective multiplicities m_1,m_2,...,m_n.

We have,

f(x)=(x+3)^2(x-5)^6

On comparing this with (i), we get

c_1=-3,m_1=2

c_2=5,m_2=6

It means, -3 is a zero with multiplicity 2 and 5 is a zero with multiplicity 6.

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Step-by-step explanation:


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3 years ago
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Step-by-step explanation:

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