The HTT mutation that causes the Huntington's Disease involves a DNA segment otherwise known as a CAG trinucleotide repeat.
C.<span>trees going dormant in winter to survive unfavorable conditions</span>
These anatomical structures are the following:
1. The urine itself which serves as an antiseptic, washing potentially harmful bacteria out from the body during normal urination
2. The ureters join into the bladder in a manner designed to prevent urine from backing up into the kidney when the bladder squeezes urine out through the urethra.
3. The prostate gland in men that secretes infection-fighting substance.
4. The immune system defenses and antibacterial substance in the mucous lining of the bladder eliminate many organisms.
5. The vagina of a healthy women, it is colonized by lactobacilli, a beneficial microorganisms that maintain a highly acidic environment (low pH) that is hostile to other bacteria. It also produces hydrogen peroxide, which help eliminate bacteria and reduces the ability of Escherichia coli (E. coli) to adhere to vaginal cells that is the major bacterial culprit in urinary tract infection.
Answer:
Explanation:
The Genotype of the woman is XCbXN
The man XNY
Since the allele for the color blindness is carried on one of the X -chromosomes of the carrier mother, then the male children will be color blind or carrier deopending on the defective gene they inherited. Since they will receive the defective or normal allele from the mothers,but the female will carriers or normal because they will inherit either defective allele or normal allele from the mother,but normal X allele from the father.
Assuming the colorbind gene was inherited by One of the boys, and the girls take the defective genes
1. XNY vs XCbXN.Then the one of the boys will be colorblind and the one of girls will be carriers. XNXCb, XNXN, XCbY,XNY 50 %
2.If the two boys take the effective genes from the mothers. and none of the girls take the defective alelle
Then the two boys will be colorblind and the girls will be carrries XcbY,XcbY and XNXN XNXN.(normal girls).
The proportions that will be the females since the girls can only take the defective allele from one of the normal and defective allele from the mother. Assuming the girls take the defective allele from the mothers and take normal from the father,they will all be carriers,since the X of the father is normal.
They can not have a color blind girl.Since the father is normal It takes two colorblind X-chromosome to give a girl.
