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Serhud [2]
3 years ago
10

18. Solve the quadratic equation by using the graph.

Mathematics
1 answer:
deff fn [24]3 years ago
6 0

Answer:

x= -1 and 1

Step-by-step explanation:

look at where y=0 and what x value intersects it

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The product of k and 6
mote1985 [20]

Answer:

6k

Step-by-step explanation:

Is that what you wanted

Hope this helps.

4 0
3 years ago
Sara resd 81 pages in her book colin resd 64 pages in his book.How many more pages did sara resd than colin
Olin [163]

Answer:

Sara read 17 more

Step-by-step explanation:

81-64=17

64+17=84

7 0
4 years ago
Read 2 more answers
23) A ball is launched into the air. The function h=-16 +126 gives the height of the
Paul [167]

The equation is missing 't' terms. The correct equation is:

h=-16t^2+126t

Answer:

(a) 248.06 ft

(b) 7.875 s

Step-by-step explanation:

Given:

Height of ball in air above ground is given as:

h=-16t^2+126t

(a)

At maximum height, the speed of the ball is 0 momentarily. Speed is nothing but rate of change of height which is the first derivative of height with time. Therefore,

At maximum height:

Speed = 0

h'=0\\-16(2t)+126=0\\-32t+126=0\\32t=126\\t=\frac{126}{32}=3.9375\ s

Now, maximum height is obtained by plugging in t=3.9375. Thus,

h_{max}=-16(3.9375)^2+126(3.9375)\\h_{max}=-248.0625+496.125=248.0625\ ft

Therefore, the maximum height of the ball is 248.06 ft. (Rounded to nearest hundredth)

(b)

Now, total time of travel of the ball is the sum of time taken to reach maximum height and the time taken from maximum height to the bottom.

Also, time taken for upward journey would be same as that of downward journey. Therefore, total time taken is twice that of the upward journey.

We have,

Time to reach maximum height, t = 3.9375\ s

Therefore, total time the ball was in air = 2(t)=2\times 3.9375=7.875\ s

Hence, the ball was in the air for 7.88 s. (Rounded to nearest hundredth)

3 0
3 years ago
The third term in an arithmetic sequence is 10 and the fifth term is 26.If the first term is a1,which is an equation for the nth
dexar [7]
Just plug in 3 for n and then 5 for n to see if an turns out to be 10 and 26.

n=3:
A) an = 8*3+10 = 34
B) an = 8*3 - 14 = 10  OK
C) an = 16*3+10 = 58
D) an = 16*3 - 38 = 10 OK

n=5:
B) an = 8*5-14 = 26 OK
D) an = 16*5 - 38 = 42

So the answer is B
5 0
3 years ago
$2.95+$3.09+$5.85+$4.10
Gnom [1K]

Step-by-step explanation:

the value of P(B|A)P(B∣A), rounding to the nearest thousandth

3 0
3 years ago
Read 2 more answers
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