Question

Use the quadratic formula to solve x2 + 9x + 10 = 0. What are the solutions to the equation?

Answer 1

Answer:

$\large\boxed{x=\dfrac{-9\pm\sqrt{41}}{2}}$

Step-by-step explanation:

$\text{The quadratic formula of}$

$ax^2+bx+c=0$

$\text{If}\ b^2-4a0,\ \text{then the equation has two solutions}\ x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\=========================================$

$\text{We have}\ x^2+9x+10=0\\\\a=1,\ b=9,\ c=10\\\\\text{substitute:}\\\\b^2-4ac=9^2-4(1)(10)=81-40=41>0\qquad _{\text{two solutions}}\\\\\sqrt{b^2-4ac}=\sqrt{41}\\\\x=\dfrac{-9\pm\sqrt{41}}{2(1)}=\dfrac{-9\pm\sqrt{41}}{2}$

Answer 2

Answer:

The solution of given quadratic equation  =  [-9 ± √41]/2

Step-by-step explanation:

Points to remember

solution of a quadratic equation ax² + bx + c = 0

x = [-b ± √(b² - 4ac)]/2a

It is given that, x² + 9x + 10 = 0.

To find the solution

Here a = 1, b= 9 and c = 10

x = [-b ± √(b² - 4ac)]/2a

 = [-9 ± √(9² - 4*1*10)]/2*1

 = [-9 ± √(81 - 40)]/2

 =  [-9 ± √(41)]/2

 = [-9 ± √41]/2

Therefore the solution of given quadratic equation  =  [-9 ± √41]/2