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2 years ago

Relate a vertical line test to understanding functions.

Mathematics

1 answer:

xenn [34]2 years ago

6 0

Answer:

Each vertical line drawn through the graph will intersect a relation in only one location

Step-by-step explanation:

We know that a vertical line test is done to test whether the graph or the given relation is a function or not and it states that:

Each vertical line parallel to the co-domain drawn on a graph will intersect the graph exactly once.

i.e. there is a unique image of each pre-image.

Hence, option: C is the correct answer.

Each vertical line drawn through the graph will intersect a relation in only one location.

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Let u = in x and v = in y. Write in(x3y2) in terms of u and v

sleet_krkn [62]

Answer:

Step-by-step explanation:

you mean u=ln x,v=ln y

ln(x^3y^2)=lnx^3+ln y^2

=3 ln x+2 ln y

=3u+2v

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2 years ago

Which equation represents g(x)?

Sergeeva-Olga [200]

Answer:

There's not enough information to determine the answer... is there more to this?

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2 years ago

Use Newton's method with initial approximation x1 = −2 to find x2, the second approximation to the root of the equation x3 + x +

nevsk [136]

Answer:

$x_2 \approx -1.769$

Step-by-step explanation:

Let $f(x)=x^3+x+7$

So $f'(x)=3x^2+1$

$x_{n+1}=x_n-\frac{f(x_n)}{f'(x_n)}$

Let $x_1=-2$

We are going to find $x_2$

So we are evaluating $-2-\frac{f(-2)}{f'(-2)}$

First step find f(-2)

Second step find f'(-2)

Third step plug in those values and apply PEMDAS!

$f(-2)=(-2)^3+(-2)+7=-8-2+7=-10+7=-3$

$f'(-2)=3(-2)^2+1=3(4)+1=12+1=13$

$x_2=-2-\frac{-3}{13} \\\\ x_2=\frac{-26+3}{13} \\\\ x_2=\frac{-23}{13} \\\\ x_2 \approx -1.769$

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2 years ago

Solve for x. A) 0.9 B) 160 C) 10 D) 1.1

creativ13 [48]

Answer:

C .10

Step-by-step explanation:

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Answer:

A. x≥4 ( red on 4)

B. x≤4 ( red on 4)

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D. x<4 (blue on 4)

Step-by-step explanation:

illustrated

A. x≥4 ( red on 4)

B. x≤4 ( red on 4)

C. x>4 (blue on 4)

D. x<4 (blue on 4)

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2 years ago

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