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4 years ago

Geometry angles help me out trynna get 100

Mathematics

2 answers:

yulyashka [42]4 years ago

8 0

Answer:

sorry I don't no the answer

Ber [7]4 years ago

6 0

Answer:

Supplementary angles

Step-by-step explanation:

These are angles adding up to 180 when put together and they are normally on a straight line.

HOPE IT HELPED

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What is the least common denominator of 9,8,6,5

Alex

Answer:

Step-by-step explanation:

LCD = 1

Equivalent Fractions with the LCD

9 = 9/1

8 = 8/1

6 = 6/1

5 = 5/1

Solution:

Rewriting input as fractions if necessary:

9/1, 8/1, 6/1, 5/1

For the denominators (1, 1, 1, 1) the least common multiple (LCM) is 1.

LCM(1, 1, 1, 1)

Therefore, the least common denominator (LCD) is 1.

Calculations to rewrite the original inputs as equivalent fractions with the LCD:

9 = 9/1 × 1/1 = 9/1

8 = 8/1 × 1/1 = 8/1

6 = 6/1 × 1/1 = 6/1

5 = 5/1 × 1/1 = 5/1

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4 years ago

Solve the equation y= 3x-1 for x.

vaieri [72.5K]

Answer:

x = y/3 plus 1/3

Step-by-step explanation:

isolate the variable by dividing each side by factors that dont contain the variable.

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3 years ago

after the first hour of the monsoon 23 mm precipitation has fallen after the second hour a total of 61 mm of precipitation at Fa

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38mm

61mm-23mm is 38mm

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4 years ago

Let vector F = (6 x^2 y + 2 y^3 + 4 e^x) i + (7 e^{y^2} + 54 x) j . Consider the line integral of vector F around the circle of

balu736 [363]

Denote the circle of radius $a$ by $C$ . $C$ is simple and closed, so by Green's theorem the line integral reduces to a double integral over the interior of $C$ (call it $D$ ):

$\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\int_C(6x^2y+2y^3+4e^x)\,\mathrm dx+(7e^{y^2}+54x)\,\mathrm dy$

$=\displaystyle\iint_D\left(\frac{\partial(7e^{y^2}+54x)}{\partial x}-\frac{\partial(6x^2y+2y^3+4e^x)}{\partial y}\right)\,\mathrm dx\,\mathrm dy$

$=\displaystyle\iint_D(54-6x^2-6y^2)\,\mathrm dx\,\mathrm dy$

$D$ is a circle of radius $a$ , so we can write the double integral in polar coordinates as

$\displaystyle\iint_D(54-6x^2-6y^2)\,\mathrm dx\,\mathrm dy=\int_0^{2\pi}\int_0^a(54-6r^2)r\,\mathrm dr\,\mathrm d\theta$

a. For $a=1$ , we have

$\displaystyle\int_0^{2\pi}\int_0^1(54-6r^2)r\,\mathrm dr\,\mathrm d\theta=2\pi\int_0^1(54r-6r^3)\,\mathrm dr=\boxed{51\pi}$

b. Let $I(a)$ denote the integral with unknown parameter $a$ ,

$I(a)=12\pi\int_0^a(9r-r^3)\,\mathrm dr\,\mathrm d\theta$

By the fundamental theorem of calculus,

$I'(a)=12\pi(9a-a^3)$

$I(a)$ has critical points when

$12\pi(9a-a^3)=12\pi a(9-a^2)=0\implies a=0,a=\pm3$

If $a=0$ , then line integral is 0, so we ignore that critical point. For the other two, we would find $I(\pm3)=243\pi$ .

8 0

3 years ago

Which number is closest to the value of the upper quartile?

Allisa [31]

Answer:

180 is closest to upper quartile

Step-by-step explanation:

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3 years ago