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77julia77 [94]
3 years ago
15

If DJL = EGS, which segment in EGS corresponds to DL?

Mathematics
1 answer:
Advocard [28]3 years ago
6 0
I think the answer is c
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Help look at my photo
STALIN [3.7K]

Answer:

  • A  x² +2x +4
  • D  x² +10x +26

Step-by-step explanation:

One way to determine if the equation has any real solutions is to look at its discriminant. For the equation ax²+bx+c = 0, the discriminant is ...

  d = b² -4ac

When the discriminant is negative, both solutions to the quadratic are complex. There are no real solutions in that case.

We can find the discriminant values to be ...

  A: d = 2² -4(1)(4) = -12 . . . . no real zeros

  B: d = 0² -4(3)(-5) = 60 . . . two real zeros

  C: d = 8² -4(-2)(0) = 64 . . . two real zeros

  D: d = 10² -4(1)(26) = -4 . . .no real zeros

Expressions A and D have no real zeros.

_____

<em>Comment on the question</em>

You are given an <em>expression</em>, not an <em>equation</em>. There is no equal sign. Hence, we cannot talk about <em>solutions</em>. We can only talk about <em>zeros</em>, values of x that make the expression have a value of zero.

5 0
3 years ago
9 is added to a number and multiplied by 7. The result is 84.​
bearhunter [10]

Answer:

<h2> 12 because 9+3 = 12 12 • 7 = 84</h2>

Step-by-step explanation:

<h2>Hopes this helps. Mark as brainlest plz!</h2>
4 0
3 years ago
Read 2 more answers
PLZ HURRY IT'S URGENT!!!!!!!!
olga2289 [7]

Let's solve your equation step-by-step.

6+2s−8s=18

Step 1: Simplify both sides of the equation.

6+2s−8s=18

6+2s+−8s=18

(2s+−8s)+(6)=18(Combine Like Terms)

−6s+6=18

−6s+6=18

Step 2: Subtract 6 from both sides.

−6s+6−6=18−6

−6s=12

Step 3: Divide both sides by -6.

−6s/−6

=12/−6

s=−2

Answer:

s=−2

3 0
4 years ago
Read 2 more answers
What’s the slope (rate of change) for the red?
ZanzabumX [31]
Um I think it is 2,1 count over 2 then go up1
8 0
3 years ago
Rita goes for a bike ride on a trail by her house. After 15 minutes of riding she sees a mile marker. When she reaches the third
lana66690 [7]

Given:

Rita covered 1 mile in 15 minutes.

She covered 3 miles in 30 minutes.

To find:

The rate at which she is riding.

Solution:

Let y be the number of miles covered in x minutes.

Rita covered 1 mile in 15 minutes. So, the point is (15,1).

She covered 3 miles in 30 minutes. So, the point is (30,3).

Slope of the line:

m=\dfrac{y_2-y_1}{x_2-x_1}

m=\dfrac{3-1}{30-15}

m=\dfrac{2}{15}

Therefore, she is riding \dfrac{2}{15} miles per minute.

8 0
3 years ago
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