Answer:
40 mph
Step-by-step explanation:
To find the maximum speed at which the car can travel, as the distance it requires to stop is 168 feet, we just need to use the value of d = 168 in the equation, and then find the value of s:
168 = 0.05s^2 + 2.2s
0.05s^2 + 2.2s - 168 = 0
Using Bhaskara's formula: we have:
Delta = 2.2^2 + 4*0.05*168 = 38.44
sqrt(Delta) = 6.2
s1 = (-2.2 + 6.2)/0.1 = 40 mph
s2 = (-2.2 - 6.2)/0.1 = -84 mph (a negative value does not make sense as 's' is the speed of the car)
So the maximum speed of the car is 40 mph
Answer:
Step-by-step explanation:
The given radical expression is;
We multiply both the numerator and the denominator by the conjugate of
which is 
The denominator is now difference of two squares;
Simplify:
Subsitute values for x and evaluate to get values for y
when x=5, y=1
when x=0, y=-1
when x=-5, y=-3
remember, ordered pairs are in (x,y) form
so 3 ordered pairs are
(5,1)
(0,-1)
(-5,-3)
Step-by-step explanation:
100 = 12
300 + 50 = 36 + 6 = 42 L
1360/200
13.6/2
6.8
It is a finite decimal, but if you want repeating, there are zeroes that follow, like so:
6.8000000000000 . . . (and on to infinity)
