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Ierofanga [76]
3 years ago
6

When x=1, find the value of y 1) -3 2) -1 3)1 4)-4

Mathematics
1 answer:
Molodets [167]3 years ago
3 0

Answer:

y = -3

Step-by-step explanation:

The equation of the line is y = -x -2

We plug in the given x value into the equation to find y.

y = -(1) - 2

Simplify.

y = -3

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HELP with these questions
zlopas [31]

<u>Step-by-step explanation:</u>

transform the parent graph of f(x) = ln x        into f(x) = - ln (x - 4)  by shifting the parent graph 4 units to the right and reflecting over the x-axis

(???, 0): 0 = - ln (x - 4)

            \frac{0}{-1} = \frac{-ln (x - 4)}{-1}

            0 = ln (x - 4)

            e^{0} = e^{ln (x - 4)}

             1 = x - 4

          <u> +4 </u>  <u>    +4 </u>

             5 = x

(5, 0)

(???, 1): 1 = - ln (x - 4)

            \frac{0}{-1} = \frac{-ln (x - 4)}{-1}

            1 = ln (x - 4)

            e^{1} = e^{ln (x - 4)}

             e = x - 4

          <u> +4 </u>   <u>    +4 </u>

         e + 4 = x

          6.72 = x

(6.72, 1)

Domain: x - 4 > 0

                <u>  +4 </u>  <u>+4  </u>

               x       > 4

(4, ∞)

Vertical asymptotes: there are no vertical asymptotes for the parent function and the transformation did not alter that

No vertical asymptotes

*************************************************************************

transform the parent graph of f(x) = 3ˣ        into f(x) = - 3ˣ⁺⁵  by shifting the parent graph 5 units to the left and reflecting over the x-axis

Domain: there is no restriction on x so domain is all real number

(-∞, ∞)

Range: there is a horizontal asymptote for the parent graph of y = 0 with range of y > 0.  the transformation is a reflection over the x-axis so the horizontal asymptote is the same (y = 0) but the range changed to y < 0.

(-∞, 0)

Y-intercept is when x = 0:

f(x) = - 3ˣ⁺⁵

      = - 3⁰⁺⁵

      = - 3⁵

      = -243

Horizontal Asymptote: y = 0  <em>(explanation above)</em>

5 0
4 years ago
50 point to the person that can answer this:
ale4655 [162]

Answer:

  • B. The constant in the expression is 1/2

Step-by-step explanation:

<u>Given formula for the area of a triangle</u>

  • A = 1/2bh

<u>Statements to confirm</u>

A. The coefficient of is b.

  • False. b is variable, 1/2 is coefficient

B. The constant in the expression is 1/2

  • True

C. There is one term in the expression.

  • False. There are 3 terms, one constant and two variables

D. There is one variable in the expression.

  • False. There are two variables, b and h

<em>Note. </em>

<em>Assumed 1/2 is given in Option B, otherwise all statements are false</em>.

7 0
3 years ago
I’ll mark brainliest. I really need help on this pleaseee!!
Nadusha1986 [10]
It is letter B because that is right
4 0
3 years ago
Simplify. Final answers should be written in standard form. (Reminder: in order to indicate an exponent you must use the carrot
rosijanka [135]

Answer:

-12w^3+32w^2-136w+80

Step-by-step explanation:

4(2-3w)(w^2-2w+10)

multiply first two:

(8-12w)(w^2-2w+10)

multiply:

8w^2-16w+80-12w^3+24w^2-120w

simplify:

-12w^3+32w^2-136w+80

7 0
3 years ago
Find the length of the third side. If necessary, write in simplest radical form
katrin [286]

HERE,

the \huge{\triangle}is a right angle traingle.

length of one side=\bold{ 1  } 

length of another side =\bold{\sqrt{3}  } 

so,

the length of third side=

  • \bold{\sqrt{(1)^{2} +({\sqrt{3}})^{2}}   } 

  • \bold{\sqrt{1+3}   } 

  • \bold{\sqrt{4}   } 

  • {\huge{\fcolorbox{aqua}{navy}{\fcolorbox{yellow}{blue}{\bf{\color{yellow}{2}}}}}}

\therefore,the length third side of the traingle is 2.

3 0
3 years ago
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