Trapezoidal is involving averageing the heights
the 4 intervals are
[0,4] and [4,7.2] and [7.2,8.6] and [8.6,9]
the area of each trapezoid is (v(t1)+v(t2))/2 times width
for the first interval
the average between 0 and 0.4 is 0.2
the width is 4
4(0.2)=0.8
2nd
average between 0.4 and 1 is 0.7
width is 3.2
3.2 times 0.7=2.24
3rd
average betwen 1.0 and 1.5 is 1.25
width is 1.4
1.4 times 1.25=1.75
4th
average betwen 1.5 and 2 is 1.75
width is 0.4
0.4 times 1.74=0.7
add them all up
0.8+2.24+1.75+0.7=5.49
5.49
t=time
v(t)=speed
so the area under the curve is distance
covered 5.49 meters
Answer:
56
Step-by-step explanation:
A∆ = BH/2
Area of a parm is BH (base x height) so we multiply area of triangle by 2.
28 x 2 = 56. There you go
Step-by-step explanation:
For no 1...
The range is [ -9, -7, 1]
For no 2....
The range is [-12, -10, -2]
For no 3.....
The range is [-11, -8, 4]
Answer:
49
Step-by-step explanation:
