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alexgriva [62]
3 years ago
14

Definition of militarism and alliances and imperialism and nasionalisme. ​

Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
8 0

Answer:

The war started mainly because of four aspects: Militarism, Alliances, Imperialism and Nationalism. This is because big armies become potential threats to other countries, other countries started forcing alliances in order to secure land. ... The overall cause of World War was the assassination of Archduke Franz Ferdinand.

Step-by-step explanation:

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Can someone please help with this question pleaseee
Ulleksa [173]

Answer: Choice C) 10.5

The distance from A to C is 7 units (count out the spaces between the two points, or subtract y coordinates 4-(-3) = 4+3 = 7)

Let AC = 7 be the base of the triangle. You might want to rotate the image so that AC is laying horizontally rather than being vertical.

Now move to point P. Walk 3 spaces to the right until you land on segment AC. This shows that the height of the triangle is 3 when the base is AC = 7.

base = 7, height = 3

area of triangle = (1/2)*base*height

area of triangle = 0.5*7*3

area of triangle = 10.5 square units

7 0
3 years ago
Read 2 more answers
Write the following expression using exponents.<br> 4x4x4x4 =
Jlenok [28]

Answer:

4^4

Step-by-step explanation:

Since there are four 4's, it is to the 4th power.

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3 years ago
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you deposit $2,000 in an account that earns simple interest. after 6 months the account earns $210 in interest. what is the annu
Luden [163]

Answer:

21%

Step-by-step explanation:

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8 0
3 years ago
Please help!! what is the length of the line
UkoKoshka [18]

Answer:

\sqrt136 (option D)

<h3>Step-by-step explanation:</h3>

6 0
3 years ago
Evaluate the line integral for x^2yds where c is the top hal fo the circle x62 _y^2 = 9
natulia [17]
Parameterize C by

\mathbf r(t)=\langle x(t),y(t)\rangle=\langle3\cos t,3\sin t\rangle

where 0\le t\le\pi. Then the line integral is

\displaystyle\int_Cx^2y\,\mathrm dS=\int_{t=0}^{t=\pi}x(t)^2y(t)\left\|\frac{\mathrm d\mathbf r(t)}{\mathrm dt}\right\|\,\mathrm dt
=\displaystyle\int_{t=0}^{t=\pi}(3\cos t)^2(3\sin t)\sqrt{(-3\sin t)^2+(3\cos t)^2}\,\mathrm dt
=\displaystyle3^4\int_{t=0}^{t=\pi}\cos^2t\sin t\,\mathrm dt

Take u=\cos t, then

=\displaystyle-3^4\int_{u=1}^{u=-1}u^2\,\mathrm du
=\displaystyle3^4\int_{u=-1}^{u=1}u^2\,\mathrm du
=\displaystyle2\times3^4\int_{u=0}^{u=1}u^2\,\mathrm du
=54
6 0
3 years ago
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