Domain: (-infinity, +infinity) Range: [0, +infinity)
Solution
For this case we can take square root in both sides and we have:
![3x-5=\pm\sqrt[]{19}](https://tex.z-dn.net/?f=3x-5%3D%5Cpm%5Csqrt%5B%5D%7B19%7D)
And solving for x we got:
![x=\frac{5\pm\sqrt[]{19}}{3}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B5%5Cpm%5Csqrt%5B%5D%7B19%7D%7D%7B3%7D)
then the solutions for this case are:
B and E
Answer:
D. reflection across a vertical line
Step-by-step explanation:
Reflection is basically a mirror image. Since you can see that the first triangle is flipped over to get the second one, this is a reflection.
It is not a vertical translation; this means that the triangle shifted up or down.
It is not a horizontal translation, this means that the triangle shifted left or right.
It is not a rotation about point A either, this would have meant that the triangle spun around.
1/9 times 3/1 = 1/3. Now divide 1/3 by 5 or multiply by 1/5 and you get 1/15. There's your answer
