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Phantasy [73]
4 years ago
12

How do I do this problem??

Mathematics
1 answer:
KiRa [710]4 years ago
8 0
First find the difference of the numerator. to do this multiply 1/x by 2 and 1/2 by x. you should get (2-x)/2x. now moving on to the whole fraction. then multiply the (2-x)/2x by 2x and the (x-2) by 2x. you should get (2-x)/(2x)(x-2). now factor out a negative from the (x-2) at the denominator to get -(2-x). so now you can cancel the (2-x) from the numerator and denominator! the answer will be 1/-2x! :)
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Arturiano [62]

Answer:

A): Right triangle (Right angle)

B): Scalene triangle (No equal angles or side lengths)

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3 years ago
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You are constructing a concrete landing pad for a helicopter. You have 4704 cubic feet of concrete.
MAVERICK [17]

a) We have to calculate the height of the pad.

We know that the volume will be 4704 cubic feet.

We also know that the base of the pad is a square of side length 56 feet.

As the volume is the area of the base times the height, we can find the height by dividing the volume by the base area:

\begin{gathered} V=A_b\cdot h \\ h=\frac{V}{A_b}=\frac{4704\text{ ft}^3}{(56\text{ ft})^2}=\frac{4704}{3136}\text{ ft}=1.5\text{ ft} \end{gathered}

The height is 1.5 feet.

b) Now, we have a circular pad of which we know the height (1.5 feet) and the volume (4705 ft³). The area of the base will have to be the same as the are of the square: 3136 ft².

The area of this circular pad can be expressed as πD²/4, so we can calculate the diameter D as:

\begin{gathered} A=3136 \\ \frac{\pi D^2}{4} \\ D^2=3136*\frac{4}{\pi} \\ D^2=3136*\frac{4}{3.14} \\ D^2=3994.9045 \\ D=\sqrt{3994.9045} \\ D\approx63.21 \end{gathered}

The diameter is approximately 63.21 feet.

Answer:

a) The pad will be 1.5 feet thick

b) The diameter will be 63.21 feet.

3 0
1 year ago
Verify the identity. <br> tan (x + pi/2) = -cot x
Leno4ka [110]
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alexgriva [62]

Answer:

y=(x-2)(x+2)

Step-by-step explanation:

The table and graph show the line crossing the x axis at -2 and +2.  That means when x is either of those two values, y will be 0.

If we set each equation to zero, we should find those two values of x.  I'll skip right to the second equation, since I can see that it would meet those criteria:

y=(x-2)(x+2)

0=(x-2)(x+2)

x = 2 and x = -2

See attachment.

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Part A: 5.25
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Part B: 8 hrs because
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