Answer:
Step-by-step explanation:
We have to find the quotient of the following division, 
.
Now,
= ![- \frac{3}{4} p^{[- 4 - (- 12)]} q^{[-6 - (- 3)]}](https://tex.z-dn.net/?f=-%20%5Cfrac%7B3%7D%7B4%7D%20p%5E%7B%5B-%204%20-%20%28-%2012%29%5D%7D%20q%5E%7B%5B-6%20-%20%28-%203%29%5D%7D)
{Since all the terms in the expression are in product form, so we can treat them separately}
{Since we know the property of exponent as 
}
= 
= (Answer)
{Since we know, 
}
Answer:
Step-by-step explanation:
35 marks out of 40<u> as a fraction:</u>
35 / 40
<u>As a percentage:</u>
<u></u>![\sf \frac{35}{40} * 100 \ \%\\\\0.875 * 100 \ \%\\\\87.5 \ \%\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Csf%20%5Cfrac%7B35%7D%7B40%7D%20%2A%20100%20%5C%20%5C%25%5C%5C%5C%5C0.875%20%2A%20100%20%5C%20%5C%25%5C%5C%5C%5C87.5%20%5C%20%5C%25%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>
Answer: y= 1200 (1.025)^t
Step-by-step explanation:
Hi, to answer this question we have to apply an exponential growth function:
A = P (1 + r) t
Where:
p = original population
r = growing rate (decimal form)
t= years
A = population after t years
Replacing with the values given:
1200= 1200 (1+ 2.5/100)^5
1200= 1200 (1+ 0.025)^5
1200= 1200 (1.025)^5
For the number of rabbits, y, at the end of t years
y= 1200 (1.025)^t
Feel free to ask for more if needed or if you did not understand something.
4% outta 1425 is 57| The amount is 57.
