We know that
the equation of the vertical parabola in the vertex form is
<span>y=a(x-h)²+k
</span>where
(h,k) is the vertex of the parabola
if a> 0 then
the parabola opens upwards
if a< 0
then the parabola open downwards
in this problem we have
f(x)=−5(x+7)²<span>+6
</span>a=-5
so
a< 0 -------> the parabola open downwards
the vertex is the point (-7,6) is a maximum
the answer is the option<span>
a = -5, opens down</span>
see the attached figure
202 because you can round it to 200
Answer:
Equation of midsegment line: y = (-1/4)x + 2.
Step-by-step explanation:
If the parallel sides of a trapezoid are contained by the lines:-
y = (-1/4)x +5 and y = (-1/4)x - 1
Midsegment of any trapezoid is the line segment
1. that is parallel to pair of parallel side of trapezoid and
2. that passes through the middle of the trapezoid and cuts the other two sides into equal-half.
It means the midsegment would have same slope as the parallel lines and y-intercept would be in the middle of intercepts of parallel lines.
So y = mx + b
where m = -1/4 and b = (5 - 1)/2 = 4/2 = 2.
Hence, the equation of midsegment would be y = (-1/4)x + 2.
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