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Ghella [55]
4 years ago
12

If k = 23 and m -14, what is ✓k + m? Submit

Mathematics
1 answer:
Elena-2011 [213]4 years ago
6 0

Answer:

3

Step-by-step explanation:

Evaluate:

Sqrt of k = 32 + m = -14

Sqrt of 32-14 = 9

Sqrt of 9 = 3

Therefore, our answer is 3!

Btw sqrt means: square root

Hope this helps! Have a good day!

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A ball is launched upward at 14 m/s from a platform 30 m high.Find the maximum height the ball will reach and how long it will t
BartSMP [9]

Answer:

The ball will reach a maximum height of 39.993 meters after 1.428 seconds.

Step-by-step explanation:

Let suppose that no non-conservative forces acts on the ball during its motion, then we can determine the maximum height reached by the Principle of Energy Conservation, which states that:

K_{1}+U_{g,1} = K_{2}+U_{g,2} (1)

Where:

K_{1}, K_{2} - Initial and final translational kinetic energies, measured in joules.

U_{g,1}, U_{g,2} - Initial and final gravitational potential energies, measured in joules.

By definition of translational kinetic energy and gravitational potential energy we expand and simplify the expression above:

\frac{1}{2}\cdot m\cdot v_{2}^{2}+m\cdot g\cdot y_{2}= \frac{1}{2}\cdot m\cdot v_{1}^{2}+m\cdot g\cdot y_{1} (2)

Where:

m - Mass of the ball, measured in kilograms.

g - Gravitational acceleration, measured in meters per square second.

v_{1}, v_{2} - Initial and final speed of the ball, measured in meters per second.

y_{1}, y_{2} - Initial and final heights of the ball, measured in meters.

The final height of the ball is determined by the following formula:

v_{2}^{2}+2\cdot g\cdot y_{2} = v_{1}^{2}+2\cdot g\cdot y_{1}

v_{1}^{2}-v_{2}^{2}+2\cdot g \cdot y_{1}=2\cdot g\cdot y_{2}

y_{2} = y_{1}+\frac{v_{1}^{2}-v_{2}^{2}}{2\cdot g} (3)

If we know that y_{1} = 30\,m, v_{1} = 14\,\frac{m}{s}, v_{2} = 0\,\frac{m}{s} and g = 9.807\,\frac{m}{s^{2}}, the maximum height that the ball will reach is:

y_{2} = 30\,m + \frac{\left(14\,\frac{m}{s} \right)^{2}-\left(0\,\frac{m}{s} \right)^{2}}{2\cdot \left(9.807\,\frac{m}{s^{2}} \right)}

y_{2} = 39.993\,m

The ball will reach a maximum height of 39.993 meters.

Given the absence of non-conservative forces, the ball exhibits a free fall. The time needed for the ball to reach its maximum height is computed from the following kinematic formula:

t = \frac{v_{2}-v_{1}}{-g} (4)

If we know that v_{1} = 14\,\frac{m}{s}, v_{2} = 0\,\frac{m}{s} and g = 9.807\,\frac{m}{s^{2}}, then:

t = \frac{0\,\frac{m}{s}-14\,\frac{m}{s}  }{-9.807\,\frac{m}{s^{2}} }

t = 1.428\,s

The ball will take 1.428 seconds to reach its maximum height.

6 0
3 years ago
Find the function value f(x)=3x-6,f(-4)
Otrada [13]

Answer:

f(x) = -18

Step-by-step explanation:

f(x) = 3x - 6

f(-4) = 3(-4) - 6

f(-4) = -12 -6

= -18

plzz.....

mark it as a brilliant

8 0
4 years ago
Read 2 more answers
Gordan and Harry had 340 marble,altogether.After Gordan gave away 2/5 of his marbles and harry gave away 20 of his marbles, they
BARSIC [14]
109.8
you take 240 and subtract that from 2/5.Then you subtract 20 and that gives you 219.6.Since they have the same amount of marbles left,you have to divide 219.6 by 2 and your answer is 109.8
(I just used a calculator)
6 0
4 years ago
what is the radius of a circle that has a sector area of 3pi cm squared and a central angle of 2pi/3 radians
tankabanditka [31]

Answer:

r=3 cm

Step-by-step explanation:

In the attached file

6 0
4 years ago
Read 2 more answers
(x-9)(x+9) find the product
klio [65]

Method 1.

Use (a-b)(a+b)=a^2-b^2

(x-9)(x+9)=x^2-9^2=x^2-81

Method 2.

Use distributive property: (a + b)(c + d) = ac + ad + bc + bd

(x-9)(x+9)=(x)(x)+(x)(9)+(-9)(x)+(-9)(9)=x^2+9x-9x-81=x^2-81

7 0
3 years ago
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