Answer:
what i didnt understood this question from which country u r
Answer:17cm 5 cm°Step-by-step explanation:
D (0,3)
The difference in x is 12 so it would be -2 +2 which is just 0
Ok so first you know that the missing angle is going to = y+x. Then look at just half to the x so you’re looking at only a “straight line”. That means you are either seeing y+x and 2x together or y-x and y+x together. Either way, both add to 180, so that means they are equal to each other! So, you can set them equal to each other: 2x + y + x = y+ x + y - x. When you simplify that, you get y+3x = 2y so 3x = y. Then you can go back to your first equations, I used 2x + y+x = 180 and where ever there’s a y substitute in 3x. So you are left with 3x + x + 2x = 180 —> 6x = 180 so x = 30°!
Answers:
Q: What is the most they could weigh together?
A: 0.74 kg
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Q: What is the least they could weigh together?
A: 0.62 kg
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Work Shown:
x = weight of first ball
y = weight of second ball
each ball has a weight range of 0.31 kg to 0.37 kg, so,
![0.31 \le y \le 0.37](https://tex.z-dn.net/?f=0.31%20%5Cle%20y%20%5Cle%200.37)
add straight down to get
![0.31+0.31 \le x+y \le 0.37+0.37](https://tex.z-dn.net/?f=0.31%2B0.31%20%5Cle%20x%2By%20%5Cle%200.37%2B0.37)
which simplifies to
![0.62 \le x+y \le 0.74](https://tex.z-dn.net/?f=0.62%20%5Cle%20x%2By%20%5Cle%200.74)
the two soccer balls have a weight range of 0.62 to 0.74, inclusive of both endpoints.
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Without using algebra, you basically just add the smallest the two weights could be (0.31) to itself to get 0.31+0.31 = 0.62 which represents the smallest the two weights combined can be. The same happens with the largest weight of 0.37 to get 0.37+0.37 = 0.74 as the max weight of both objects together.