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3 years ago

Please help someone !!

Mathematics

2 answers:

adoni [48]3 years ago

7 0

Your answer will be letter b.)

kumpel [21]3 years ago

4 0

4X^2+2x-5
(4x^2+2x)-5
4(x^2+(0.5x))-5
4(x^2+(0.5x)+0.625-0.0625)-5
4((x+(0.25))^2-0.0625)-5
4((x+0.25)^2-0.25)-5
4(x+0.25)^2-5.25 or 4(x+1/4)^2-21/4
so the answer is A

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Assume the mean life of an iPhone is 5 years (60 months)and a standard deviation of 8 months If the age in years at which an iPh

melamori03 [73]

Answer:

Answer:

safe speed for the larger radius track u= √2 v

Explanation:

The sum of the forces on either side is the same, the only difference is the radius of curvature and speed.

Also given that r_1= smaller radius

r_2= larger radius curve

r_2= 2r_1..............i

let u be the speed of larger radius curve

now, \sum F = \frac{mv^2}{r_1} =\frac{mu^2}{r_2}∑F=

................ii

form i and ii we can write

v^2= \frac{1}{2} u^2v

⇒u= √2 v

therefore, safe speed for the larger radius track u= √2 v

8 0

2 years ago

Find the probability that a point is chosen randomly inside the rectangle is in each given shape...

Arlecino [84]

By taking the quotients between the areas, we see that:

a) P = 0.275
b) P = 0.85

<h3>How to find the probabilities?</h3>

First we need to find the areas of the 3 shapes.

For the triangle, the area is:

T = 3*5/2 = 7.5

For the blue square, the area is:

S = 3*3 = 9

For the rectangle, the area is:

R = 10*6 = 60

Now, what is the probability that a random point lies on the triangle or in the square?

It is equal to the quotient between the areas of the two shapes and the total area of the rectangle, this is:

P= (7.5 + 9)/60 = 0.275

b) The area of the rectangle that is not the square is:

A = 60 - 9 = 51

Then the probability of not landing on the square is:

P' = 51/60 = 0.85

If you want to learn more about probability:

brainly.com/question/25870256

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6 0

3 years ago

Juan wants to change the shape of his vegetable garden from a square to a rectangle, but keep the same area so he can grow the s

sergeinik [125]

The quadratic equation that would model this scenario is

$x^{2} = 2x(x-16)$

Let us take the side of the square = x

Area of the square = x²

Length of the rectangular garden = 2x

Width of the rectangular garden = x-16

So, the area of the new vegetable garden = length*width

Area of the new or rectangular vegetable garden = 2x(x-16)

<h3>What is a quadratic equation?</h3>

The polynomial equation whose highest degree is two is called a quadratic equation. The equation is given by $ax^2+bx+c$ coefficient $x^{2}$ non-zero.

Since it is given that

Area of square garden = area of the rectangular garden

$x^{2} = 2x(x-16)$

Thus, the quadratic equation that would model this scenario is

$x^{2} = 2x(x-16)$

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2 years ago

The CEO of a large electric utility claims that more than 75 percent of his customers are very satisfied with the service they r

vichka [17]

Answer:

$z=\frac{0.77-0.75}{\sqrt{\frac{0.75(1-0.75)}{100}}}=0.462$

Now we can find the p value using the alternative hypothesis with this probability:

$p_v =P(z>0.462)=0.322$

Since the p value is large enough, we have evidence to conclude that the true proportion for this case is NOT significanctly higher than 0.75 since we FAIL to reject the null hypothesis at any significance level lower than 30%

Step-by-step explanation:

Information provided

n=100 represent the random sample selected

$\hat p=0.77$ estimated proportion of students that are satisfied

is the value that we want to test

z would represent the statistic

$p_v$ represent the p value

System of hypothesis

We want to verify if more than 75 percent of his customers are very satisfied with the service they receive, then the system of hypothesis is.:

Null hypothesis: $p\leq 0.75$

Alternative hypothesis: $p > 0.75$

The statistic is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing the info given we got:

$z=\frac{0.77-0.75}{\sqrt{\frac{0.75(1-0.75)}{100}}}=0.462$

Now we can find the p value using the alternative hypothesis with this probability:

$p_v =P(z>0.462)=0.322$

Since the p value is large enough we have evidence to conclude that the true proportion for this case is NOT significanctly higher than 0.75 since we FAIL to reject the null hypothesis at any significance level lower than 30%

4 0

3 years ago

PLEASE HELP ANYONE PLEASE HELP !!!!

aliya0001 [1]

1. Square

2. (0, 0), (6,3) (6,13),(-0.5,0)

4 0

3 years ago

Read 2 more answers