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kodGreya [7K]
3 years ago
15

Geometry, Triangle in a circle. Find X show work and explain please

Mathematics
1 answer:
nikklg [1K]3 years ago
7 0

Answer: x=7

Step-by-step explanation:

By the Intersecting Secants Theorem, we know that:

(5)(x+5)=(6)(6+4)

Having this, we can find the value of "x" by solving for "x":

Applying Distributive property:

(5)(x+5)=(6)(24)\\5x+25=60

Subtract 25 from both sides of the equation:

5x+25-25=60-25\\5x=35

And finally dviding both sides of the equation by 5, we get:

\frac{5x}{5}=\frac{35}{5}\\x=7

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B

Step-by-step explanation:

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3 years ago
The mean life of a television set is 119119 months with a standard deviation of 1414 months. If a sample of 7474 televisions is
Pepsi [2]

Answer:

0.5034 = 50.34% probability that the sample mean would differ from the true mean by less than 1.1 months

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean

In this problem, we have that:

\mu = 119, \sigma = 14, n = 74, s = \frac{14}{\sqrt{74}} = 1.6275

What is the probability that the sample mean would differ from the true mean by less than 1.11 months?

This is the pvalue of Z when X = 119 + 1.1 = 120.1 subtracted by the pvalue of Z when X = 119 - 1.1 = 117.9. So

X = 120.1

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{120.1 - 119}{1.6275}

Z = 0.68

Z = 0.68 has a pvalue of 0.7517

X = 117.9

Z = \frac{X - \mu}{s}

Z = \frac{117.9 - 119}{1.6275}

Z = -0.68

Z = -0.68 has a pvalue of 0.2483

0.7517 - 0.2483 = 0.5034

0.5034 = 50.34% probability that the sample mean would differ from the true mean by less than 1.1 months

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Compare 7/8 and 5/6 ​
Ganezh [65]

Answer:

7/8 > 5/6

Step-by-step explanation:

Well look at it this way: 7/8 needs 1 more eighth until 1. 5/6 needs one more sixth until one. One eighth is smaller, so it requires a smaller amount to get to a greater number, if that makes sense. So 7/8 is greater than 5/6.

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What is √117 simplified
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Step-by-step explanation:

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