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Dmitry_Shevchenko [17]
2 years ago
10

PLEASE HELP!! Which statement about the equation is true? x + 2 = x + 4. A. The equation has no solution. B. The equation has on

e solutions. C. The equation has many solutions.
Mathematics
2 answers:
cricket20 [7]2 years ago
7 0
I think it is A. The equation has no solution. If you plugged 2 as x you would have 4=6, which is not true. If you replaced 0 into x, you would get 2=4, which is also not true.

Hope that helps!!!
Anna007 [38]2 years ago
6 0
C. The equation has many solutions
Hence x + 2 = x + 4, it could go on past x + 4 = x + 6.
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What is the equation for these tables.
marshall27 [118]

Answer:

2

Step-by-step explanation:

The y-intercept is the point on the graph where the line intersects with the y-axis. Since this point must be on the y-axis the x-value must be 0. Every coordinate on the y-axis has an x-value of 0. So, to find the answer find the y-value when x=0. In this case, when x=0, y=2. Therefore, the y-intercept is 2, also written as (0,2).

5 0
2 years ago
You want to get from a point A on the straight shore of the beach to a buoy which is 54 meters out in the water from a point B o
anyanavicka [17]

Answer:

x =\dfrac{45 \sqrt{6}}{ 2}

Step-by-step explanation:

From the given information:

The diagrammatic interpretation of what the question is all about can be seen in the diagram attached below.

Now, let V(x) be the time needed for the runner to reach the buoy;

∴ We can say that,

\mathtt{V(x) = \dfrac{70-x}{7}+\dfrac{\sqrt{54^2+x^2}}{5}}

In order to estimate the point along the shore, x meters from B, the runner should  stop running and start swimming if he want to reach the buoy in the least time possible, then we need to differentiate the function of V(x) and relate it to zero.

i.e

The differential of V(x) = V'(x) =0

=\dfrac{d}{dx}\begin {bmatrix} \dfrac{70-x}{7} + \dfrac{\sqrt{54^2+x^2}}{5} \end {bmatrix}= 0

-\dfrac{1}{7}+ \dfrac{1}{5}\times \dfrac{x}{\sqrt{54^2+x^2}}=0

\dfrac{1}{5}\times \dfrac{x}{\sqrt{54^2+x^2}}= \dfrac{1}{7}

\dfrac{5x}{\sqrt{54^2+x^2}}= \dfrac{1}{7}

\dfrac{x}{\sqrt{54^2+x^2}}= \dfrac{1}{\dfrac{7}{5}}

\dfrac{x}{\sqrt{54^2+x^2}}= \dfrac{5}{7}

squaring both sides; we get

\dfrac{x^2}{54^2+x^2}= \dfrac{5^2}{7^2}

\dfrac{x^2}{54^2+x^2}= \dfrac{25}{49}

By cross multiplying; we get

49x^2 = 25(54^2+x^2)

49x^2 = 25 \times 54^2+ 25x^2

49x^2-25x^2 = 25 \times 54^2

24x^2 = 25 \times 54^2

x^2 = \dfrac{25 \times 54^2}{24}

x =\sqrt{ \dfrac{25 \times 54^2}{24}}

x =\dfrac{5 \times 54}{\sqrt{24}}

x =\dfrac{270}{\sqrt{4 \times 6}}

x =\dfrac{45 \times 6}{ 2 \sqrt{ 6}}

x =\dfrac{45 \sqrt{6}}{ 2}

8 0
3 years ago
Two types of shipping boxes are shown below.
devlian [24]

Answer:

B. 3 square feet

Step-by-step explanation:

The formula for surface area is:

2lw+2lh+2wh

Box F's surface area is just plugging in those variables

2(3)(3)+2(3)(3)+2(3)(3)=54

Box J's surface area is the same way

2(2)(4.5)+2(2)(3)+2(4.5)(3)=57

The difference is 57-54=3

The answer is B. 3 square ft

7 0
3 years ago
When given an algebraic expression involving subtraction, why is it best to rewrite the expression using addition before identif
Ray Of Light [21]
Usually when you do expressions involving subtraction you can do Keep, Change ,Change
That means you keep the sign of the first number and change the other two signs.
It is best you rewrite the expression to addition because a lot of people don't do well with subtracting .
4 0
2 years ago
Help me plz..........
vekshin1

Answer:

The answer to your question is the third option

6 0
2 years ago
Read 2 more answers
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