12 = 400
=
15 = 15 *
= 500.
∴ 500 people took the survey
Please help me with this question, image attached.
2 answers:
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Answer:
3544
Step-by-step explanation:
This is a problem of compound growth. The formula is
Where F is the value in the future (in this case, the population after 13 years)
P is the intial amount (here, the initial population of 2000, so P = 2000)
r is the rate of growth (here, it is 4.5%, in decimal, 0.045)
t is the time frame (here, it is 13 years, so t = 13)
<em>we can plug the numbers into the formula and solve for F:</em>
<em></em>
<em>rounded to the nearest whole number, the </em><em>population after 13 years would be 3544</em>
Hello,
Vertices are on a line parallele at ox (y=-3)
The hyperbola is horizontal.
Equation is (x-h)²/a²- (y-k)²/b²=1
Center =middle of the vertices=((-2+6)/2,-3)=(2,-3)
(h+a,k) = (6,-3)
(h-a,k)=(-2,-3)
==>k=-3 and 2h=4 ==>h=2
==>a=6-h=6-2=4 (semi-transverse axis)
Foci: (h+c,k) ,(h-c,k)
h=2 ==>c=8-2=6
c²=a²+b²==>b²=36-4²=20
Equation is:
Vertices are on a line parallele at ox (y=-3)
The hyperbola is horizontal.
Equation is (x-h)²/a²- (y-k)²/b²=1
Center =middle of the vertices=((-2+6)/2,-3)=(2,-3)
(h+a,k) = (6,-3)
(h-a,k)=(-2,-3)
==>k=-3 and 2h=4 ==>h=2
==>a=6-h=6-2=4 (semi-transverse axis)
Foci: (h+c,k) ,(h-c,k)
h=2 ==>c=8-2=6
c²=a²+b²==>b²=36-4²=20
Equation is: