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My name is Ann [436]
3 years ago
5

How can x-2/3=5/6 be solved for x in one step

Mathematics
1 answer:
Kisachek [45]3 years ago
6 0

Answer:

12

Step-by-step explanation:

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Is (1, 6) a solution to this system of equations?<br> 5x + 2y = 17<br> x + 3y = 19<br> yes<br> no
Ulleksa [173]
Answer:
Yes

Explanation:
5x + 2y = 17

We are given the values (1, 6)

Substitute then into the equation

(I put a question mark to basically ask the question “is 5(1) + 2(6) equal to 17?”)

5(1) + 2(6) = 17?
5 + 12 = 17?
Yes!

Hope this helped and made sense :)
5 0
3 years ago
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Which graph best represents a kitten's weight for the first two years after birth if, from birth to 2 years old, its weight incr
elena-14-01-66 [18.8K]

Answer:

the answer would be B

Step-by-step explanation:

6 0
3 years ago
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Algebra:please answer #1 and show work
Novay_Z [31]
So 12 mins to 600 feet
35 mins=1900 feet
find the slope which is change in top over change in bottom (aka slope) so to find do
(y1-y2)/(x1-x2)
we want, per minute, so put the time as x1 and x2
x1=12
y1=600
x2=35
y2=1900
subsitutte
(600-1900)/(12-35)=-1300/-23=56.5 per minute
the answe ris 56.5 feet per minute or the last answer
4 0
3 years ago
(1) [6pts] Let R be the relation {(0, 1), (1, 1), (1, 2), (2, 0), (2, 2), (3, 0)} defined on the set {0, 1, 2, 3}. Find the foll
goldenfox [79]

Answer:

Following are the solution to the given points:

Step-by-step explanation:

In point 1:

The Reflexive closure:  

Relationship R reflexive closure becomes achieved with both the addition(a,a) to R Therefore, (a,a) is  (0,0),(1,1),(2,2) \ and \ (3,3)

Thus, the reflexive closure: R={(0,0),(0,1),(1,1),(1,2),(2,0),(2,2),(3,0), (3,3)}

In point 2:

The Symmetric closure:

R relation symmetrically closes by adding(b,a) to R for each (a,b) of R  Therefore, here (b,a) is:   (0,1),(0,2)\ and \ (0,3)

Thus, the Symmetrical closure:

R={(0,1),(0,2),(0,3)(1,0),(1,1)(1,2),(2,0),(2,2),(3,0), (3,3)}

8 0
3 years ago
X^2-4x+1=0 . RESOLVE PLS
Mkey [24]

x^2-4x+1=0\\ x^2-4x+4-3=0\\ (x-2)^2=3\\ x-2=\sqrt 3\vee x-2=-\sqrt3\\ x=2+\sqrt 3\vee x=2-\sqrt3

4 0
3 years ago
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