<img src="https://tex.z-dn.net/?f=%20%20%5Cfrac%7B8x%20%7B%20%7D%5E%7B3%7D%20%20-%2027%7D%7B4x%20%7B%7D%5E%7B2%7D%20%2B%206x%20%

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2 years ago

2B%209%20%7D%20" id="TexFormula1" title=" \frac{8x { }^{3} - 27}{4x {}^{2} + 6x + 9 } " alt=" \frac{8x { }^{3} - 27}{4x {}^{2} + 6x + 9 } " align="absmiddle" class="latex-formula">
I need help dividing these polynomials

Mathematics

1 answer:

Umnica [9.8K]2 years ago

5 0

Answer:

Step-by-step explanation:

=8x(cube)- 27 ÷ 4x(square) + 6x + 9

= 2x (3-2) + 6x - 3

= 2x + 6x - 3

= 6x(square) -3

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2 years ago

If A = (0, 0) and B = (6, 3) what is the length of overline AB ?

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A= (0,0) and B = (6,3)

We can find the length AB with the following formula:

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And replacing we got:

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So then the length AB would be $3\sqrt{5}$

Step-by-step explanation:

For this case we have the following two points:

A= (0,0) and B = (6,3)

We can find the length AB with the following formula:

$d = \sqrt{(x_B -x_A)^2 +(y_B -y_A)^2}$

And replacing we got:

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