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blsea [12.9K]
3 years ago
9

2B%209%20%7D%20" id="TexFormula1" title=" \frac{8x { }^{3} - 27}{4x {}^{2} + 6x + 9 } " alt=" \frac{8x { }^{3} - 27}{4x {}^{2} + 6x + 9 } " align="absmiddle" class="latex-formula">
I need help dividing these polynomials ​
Mathematics
1 answer:
Umnica [9.8K]3 years ago
5 0

Answer:

Step-by-step explanation:

=8x(cube)- 27 ÷ 4x(square) + 6x + 9

= 2x (3-2) + 6x - 3

= 2x + 6x - 3

= 6x(square) -3

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Answer:

Step 2 has the error

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Correction:

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Ethan rode 25.65 kilometers on Saturday and 14.23 kilometers on Sunday. About how far did Ethan ride during the two days?
vazorg [7]
So for this problem we are looking for a sum (total). So first we are going to round 25.65 to 25.7 and round 14.23 to 14.2

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Help please <br><br>number 4, 5, 6, and 7​
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Step-by-step explanation:

4. So, total time traveled is calculated by adding travel times in both directions.

From Detroit to Chicago, Charlie flew 300 miles at 150 miles per hour speed. That means that he traveled:

t1 = s / v1

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Now, let's do the same for the opposite direction. Since it's the same distance, he again flew 300 miles, but the speed this time was 100 miles per hour:

t2 = s / v2

t2 = 300 miles / 100 miles per hour

t2 = 3 hours

So, total time he traveled was t1 + t2 = 2 hours + 3 hours = 5 hours.

For the trip distance we need to add distances in both directions. We already said that the distance is the same, so the total trip distance is 300 miles + 300 miles = 600 miles.

Displacement shows how far are the ending and the starting point. Since Charlie started from Detroit, flew to Chicago, and then came back to Detroit, his ending point is the same as the starting, so the displacement is 0.

We can calculate average speed by dividing total distance with the total travel time. We already found that the total trip distance was 600 miles, and the total travel time was 5 hours. That means that:

v(average) = s(total) / t (total)

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As for the average velocity, we calculate it by dividing displacement by total travel time. Since the displacement was 0, average velocity will also be 0.

5. From the left graph we see that the object went from 0 to 2 meters (it moved 2 meters) in 1 second. That means that its speed was:

v1 = s1 / t1

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v2 = s2 / t2

v2 = 2 meters / 4 seconds

v2 = 0.5 m/s

So, our graph will show, for the first second, velocity of 2m/s, and for the next four seconds, the velocity of 0.5 m/s.

6. Again, when calculating speed, we use the equation:

v = s / t

In this case, the distance (s) is 325 miles and the time (t) is 5 hours. So, the speed will be:

v = 325 miles / 5 hours

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t = s / v

t = 325 miles / 70 mph

t = 4.64 hours.

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3 years ago
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