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blsea [12.9K]
3 years ago
9

2B%209%20%7D%20" id="TexFormula1" title=" \frac{8x { }^{3} - 27}{4x {}^{2} + 6x + 9 } " alt=" \frac{8x { }^{3} - 27}{4x {}^{2} + 6x + 9 } " align="absmiddle" class="latex-formula">
I need help dividing these polynomials ​
Mathematics
1 answer:
Umnica [9.8K]3 years ago
5 0

Answer:

Step-by-step explanation:

=8x(cube)- 27 ÷ 4x(square) + 6x + 9

= 2x (3-2) + 6x - 3

= 2x + 6x - 3

= 6x(square) -3

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Assume that the amount of beverage in a randomly selected 16-ounce beverage can has a normal distribution. Compute a 99% confide
ioda

Answer:

The question is incomplete, but the step-by-step procedures are given to solve the question.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.99}{2} = 0.005

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.005 = 0.995, so Z = 2.575.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 2.575\frac{\sigma}{\sqrt{n}}

The lower end of the interval is the sample mean subtracted by M.

The upper end of the interval is the sample mean added to M.

The 99% confidence interval for the population mean amount of beverage in 16-ounce beverage cans is (lower end, upper end).

7 0
3 years ago
What is the length of PR​
guajiro [1.7K]

Answer:

9

Step-by-step explanation:

This is because 21/7 is 3. So, you use the scale factor of 3 to divide 27/3 to get x which is 9.

3 0
2 years ago
Read 2 more answers
Find the number of letters from the word MAXIMUM where two consonants cannot occur. (Permutation)​
Hunter-Best [27]

Answer:

4!

Step-by-step explanation:

In word MAXIMUM, consonants are M & X. According to the question itself, consonants should not occur together.

So, we have to put vowels at each even position; only then the condition will be satisfied.

We can put this in 3! ways (permutations of A, I & U).  

For odd positions we can put 3-M's & a X. Total ways is 4!/3!   (as repetitions of M).

Hence, the answer is 4!/3! x 3! = 24 ways.  

24=4!.

5 0
2 years ago
Select all the expressions equivalent to: (4^5)⋅4^3 Group of answer choice 2^14 4^12 2^16 16^8 4^8 16^4
kumpel [21]

Answer:

Choices given as 2^{16}, 4^8 and 16^4 are correct.

Step-by-step explanation:

Given expression is,

(4^5)(4^3)

By applying law of exponents in the given expression,

(4^5)(4^3)=4^{5+3}

            =4^8

(4^5)(4^3)=(2^2)^5(2^2)^3

            =(2^{2\times 5})(2^{2\times 3})

            =2^{10}\times 2^6  

            =2^{16}

            =(2^4)^4

            =(16)^4

Therefore, choices given as 2^{16}, 4^8 and 16^4 are correct.

4 0
2 years ago
How do you convert 1.024242424 to a fraction
AnnyKZ [126]
The number before the decimal and the first number after the decimal and the last number
4 0
3 years ago
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