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iragen [17]
3 years ago
7

What’s 18/20 simplified

Mathematics
2 answers:
liubo4ka [24]3 years ago
6 0

\huge\text{Hey there!}

\huge\text{What's }\huge\dfrac{18}{20}\huge\text{ simplified?}

\huge\text{Both terms have the GCF} \huge\text{(Greatest Common Factor) of 2}

\huge\text{So, divide both numbers by 2.}

\huge\dfrac{18\div2}{20\div2}

\huge\text{18}\huge\div\huge\text{2 = 9}

\huge\text{9 is the numerator (top \#)}

\huge\text{20}\huge\div\huge\text{2 = 10} \huge\text{10 is the denominator (bottom \#)}

\boxed{\boxed{\huge\text{Answer: }\huge\dfrac{9}{10}}}\huge\checkmark

\text{Good luck on your assignment \& enjoy your day!}

~\frak{LoveYourselfFirst:)}

Savatey [412]3 years ago
5 0

Find the GCD (or HCF) of numerator and denominator

GCD of 18 and 20 is 2

Divide both the numerator and denominator by the GCD

18 ÷ 2

-----------

20 ÷ 2

Reduced fraction:

9

----

10

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Mariulka [41]

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3 years ago
An aeroplane X whose average speed is 50°km/hr leaves kano airport at 7.00am and travels for 2 hours on a bearing 050°. It then
Zigmanuir [339]

Answer:

(a)123 km/hr

(b)39 degrees

Step-by-step explanation:

Plane X with an average speed of 50km/hr travels for 2 hours from P (Kano Airport) to point Q in the diagram.

Distance = Speed X Time

Therefore: PQ =50km/hr X 2 hr =100 km

It moves from Point Q at 9.00 am and arrives at the airstrip A by 11.30am.

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Using alternate angles in the diagram:

\angle Q=110^\circ

(a)First, we calculate the distance traveled, PA by plane Y.

Using Cosine rule

q^2=p^2+a^2-2pa\cos Q\\q^2=100^2+125^2-2(100)(125)\cos 110^\circ\\q^2=34175.50\\q=184.87$ km

SInce aeroplane Y leaves kano airport at 10.00am and arrives at 11.30am

Time taken =1.5 hour

Therefore:

Average Speed of Y

=184.87 \div 1.5\\=123.25$ km/hr\\\approx 123$ km/hr (correct to three significant figures)

(b)Flight Direction of Y

Using Law of Sines

\dfrac{p}{\sin P} =\dfrac{q}{\sin Q}\\\dfrac{125}{\sin P} =\dfrac{184.87}{\sin 110}\\123 \times \sin P=125 \times \sin 110\\\sin P=(125 \times \sin 110) \div 184.87\\P=\arcsin [(125 \times \sin 110) \div 184.87]\\P=39^\circ $ (to the nearest degree)

The direction of flight Y to the nearest degree is 39 degrees.

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3 years ago
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Step-by-step explanation:

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