All categories

3 years ago

Did I balance this correctly?

Chemistry

1 answer:

garik1379 [7]3 years ago

6 0

Yes you balanced it correctly : CH₃CH₂CH₃ ₍g₎ + 5O₂ ₍g₎ -------> 3CO₂ ₍g₎ + 4H₂O ₍g₎

A hack to checking if its correct when they give you the structural formula of one of the species (CH₃CH₂CH₃) is to convert it to the molecular formula and if you get the same answer then it's correct.

So CH₃CH₂CH₃ is the struct-formula for the molec-formula C₃H₈

C₃H₈ + 5O₂ --------> 3 CO₂ + 4H₂O (which means your correct =D)

You might be interested in

What happens to the decaying proton during positron emission?

ivolga24 [154]

Answer:

Turns into a neutron and a gamma ray and a positron are released.

Explanation:

4 0

3 years ago

(10 points) Please help asap!!

icang [17]

Answer:

1-3 2-2 3-1

Explanation:

7 0

4 years ago

3. Heating the copper product at too high a temperature in an oxygen atmosphere results in the formation of copper( )oxde, . Wri

olya-2409 [2.1K]

First, write the equation:
Cu + O2 -> CuO
Now, balance:
2 Cu + O2 -> 2 CuO

6 0

3 years ago

Put atom in order from most to lest

Andrej [43]

Answer:

francium, caesium, helium

7 0

3 years ago

Name two compounds with more exothermic lattice energies than scandium oxide and justify your choice.

N76 [4]

Answer:

1 . $Al_2O_3$

2. $TiO_2$

Explanation:

The more stable the ionic compound, the more is it lattice energy.

The more the charge on the cation and the anion, the greater is the lattice energy.
The less the size of the cation and the anion, the greater is the lattice energy.

Scandium oxide ( $Sc_2O_3$ ) is an oxide in which $Sc^{3+}$ behaves as cation and $O^{2-}$ behaves as anion.

The compounds which has higher lattice energy than scandium oxide are:

1 . $Al_2O_3$

This is because the charge are same on the cation and the anion as in the case of the Scandium oxide but the size of the cation $Al^{3+}$ is smaller than $Sc^{3+}$ . Thus, this corresponds to higher lattice energy.

2. $TiO_2$

This is because the charge on the cation $Ti^{4+}$ is greater than that of $Sc^{3+}$ and also the size of the cation $Ti^{4+}$ is smaller than $Sc^{3+}$ . Thus, this corresponds to higher lattice energy.

3 0

3 years ago