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sineoko [7]
3 years ago
11

Name two compounds with more exothermic lattice energies than scandium oxide and justify your choice.

Chemistry
1 answer:
N76 [4]3 years ago
3 0

Answer:

1 . Al_2O_3

2. TiO_2

Explanation:

The more stable the ionic compound, the more is it lattice energy.

  • The more the charge on the cation and the anion, the greater is the lattice energy.
  • The less the size of the cation and the anion, the greater is the lattice energy.

Scandium oxide (Sc_2O_3) is an oxide in which Sc^{3+} behaves as cation and O^{2-} behaves as anion.

The compounds which has higher lattice energy than scandium oxide are:

1 . Al_2O_3

This is because the charge are same on the cation and the anion as in the case of the Scandium oxide but the size of the cation Al^{3+} is smaller than Sc^{3+}. Thus, this corresponds to higher lattice energy.

2. TiO_2

This is because the charge on the cation Ti^{4+} is greater than that of Sc^{3+} and also the size of the cation Ti^{4+} is smaller than Sc^{3+}. Thus, this corresponds to higher lattice energy.

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3 0
1 year ago
(a) Calculate the energy released by the alpha decay of 222 86Rn.
Alinara [238K]

Answer:

a). The energy released by the alpha decay of 222 Rn is to 218 Po :

= 5.596 MeV

b).The energy of the alpha particle is 5.5 MeV

c) The recoil energy of Po = 0.096 MeV

Explanation:

The equation for the alpha decay of Rn to Polonium is:

_{86}^{222}\textrm{Rn}\rightarrow _{2}^{4}\textrm{He}+_{84}^{218}\textrm{Po}

The energy of the decay process can be calculated using:

\Delta E=\Delta mc^{2}

\Delta m = Change in the mass

Mass of Po = 218.008965 u

Mass of He = 4.002603 u

Mass of Rn = 222.017576 u

\Delta m = mass of Po + mass of He - mass of Rn

=  4.002603 + 218.008965-222.017576  

= - 0.006008

\Delta E=m(931.5MeV)

\Delta E=-0.006008\times 931.5MeV

= -5.596 MeV

<u><em>The negative sign means energy is released during the process.</em></u>

b) The energy of the alpha particle is :

\frac{Po\ mass }{Rn\ mass}\times E

\frac{218.0089}{222.0175}\times \Delta E

\frac{218.0089}{222.0175}\times 5.596

= 5.494 MeV

= 5.5 MeV

c).

Recoil energy: When the parent nucleus is at rest before the decay then , there must be the some recoil of daughter nucleus to conserve the momentum.This is termed as recoil energy.

<u><em>The energy of the recoil polonium atom :</em></u>

The formula for recoil energy is :

<em>The total energy - the kinetic energy</em>

<em>= 5.596 - 5.5 </em>

<em>= 0.096 MeV</em>

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