three carbon is the most reactive
The ending carbon atoms of an extended aliphatic chain can combine in organic chemistry to create a closed system or ring, which results in cycloalkanes. These substances are referred to as cyclic substances. Cyclopropane, cyclobutane, cyclopentane, among many more, are examples.
Since cyclopropane has rings in its structural arrangement, it is less stable than the other cycloalkanes mentioned above. The positional orientation of the atoms of cycloalkane compounds, which have a tendency to emit a very high and unfavorable energy, is known as the ring strain. The ring becomes unstable and reactive due to the release of heat energy that has been trapped in its bonds and molecules.
The smaller cycloalkanes are more significantly impacted by the ring strain in terms of their structural makeup and conformational behavior.
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Answer:
a). The energy released by the alpha decay of 222 Rn is to 218 Po :
= 5.596 MeV
b).The energy of the alpha particle is 5.5 MeV
c) The recoil energy of Po = 0.096 MeV
Explanation:
The equation for the alpha decay of Rn to Polonium is:

The energy of the decay process can be calculated using:

= Change in the mass
Mass of Po = 218.008965 u
Mass of He = 4.002603 u
Mass of Rn = 222.017576 u
= mass of Po + mass of He - mass of Rn
= 4.002603 + 218.008965-222.017576
= - 0.006008


= -5.596 MeV
<u><em>The negative sign means energy is released during the process.</em></u>
b) The energy of the alpha particle is :



= 5.494 MeV
= 5.5 MeV
c).
Recoil energy: When the parent nucleus is at rest before the decay then , there must be the some recoil of daughter nucleus to conserve the momentum.This is termed as recoil energy.
<u><em>The energy of the recoil polonium atom :</em></u>
The formula for recoil energy is :
<em>The total energy - the kinetic energy</em>
<em>= 5.596 - 5.5 </em>
<em>= 0.096 MeV</em>
1.661x10 negative 24 squared
Hrxn = Q reaction / mol of reaction
mol of reaction = M * V = 10 * 1 = 10 mmol = 0.01 mol
Q water = m * C * (Tf - Ti)
= (10 + 10) (4.184) (26-20) = 502.08 J
Q reaction = - Q water = -502.08 J
Hrxn = -502.08 / (0.01) = - 50208 J = - 50.21 kJ/mol