Answer:
Coordinates of X is (7/2,9/2)
Coordinates of C is (6,7)
Explanation:
x is the midpint of DB and AC
coordinates of X = ( (5+2)/2 ,(6+3)/2)
= (7/2,9/2)
Coordinates of X is (7/2,9/2)
Let (a,b) be the coordinates of C.
Then,
coordinates of x = ((a+1)/2, (b+2)/2)
(7/2,9/2) = ((a+1)/2, (b+2)/2)
Hence,
7/2=(a+1)/2
7=a+1
a = 6
9/2 =(b+2)/2
9 =b+2
b =7
Coordinates of C is (6,7)
Answer:
Draw a perpendicular line from point A to line segment BC. Name the intersection of said line at BC “E.” You now have a right angled triangle AED.
Now, you know AD = 6 m. Next, given that the trapezoid is a normal one, you know that the midpoints of AB and DC coincide. Therefore, you can find the length of DE like so, DE = (20–14)/2 = 3 m.
Next, we will use the cosign trigonometric function. We know, cos() = adjacent / hypotenuse. Hence, cosx = 3/6 = 1/2. Looking it up on a trigonometric table we know, cos(60 degrees) = 1/2. Therefore, x = 60 degrees.
Alternatively, you could simply use the Theorem for normal trapezoids that states that the base angles will be 60 degrees. Hope this helps!
Answer:
Step-by-step explanation:
-3
+ -8
equals;
-3 - 8
Putting it in improper function way:
- 
= 
= 
in simplified form equals
Answer:
A. 21
B. 19
Step-by-step explanation:
Happy to help!
:D
