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Sav [38]
3 years ago
15

A. 231 B. 39 C. 129 D. 51

Mathematics
1 answer:
VladimirAG [237]3 years ago
3 0

Answer:

the answer is

129

Step-by-step explanation:

cyclic

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4 Consider the triangle below.
Maurinko [17]
<h2>=>> <u>Solution (part A</u>) :</h2>

Given :

▪︎Triangle AMG is an isosceles triangle.

▪︎Measure of segment AM = (x+1.4) inches

▪︎Measure of segment MG = (2x+0.1) inches

▪︎Measure of segment AG = (3x-0.4) inches

▪︎segment AG is the base of triangle AMG.

Since AG is the base of the isosceles triangle AMG, segment AM and segment MG will be equal.

Which means :

= \tt x + 1.4 = 2x + 0.1

= \tt x + 1.4 - 0.1 = 2x

=  \tt \: x + 1.3 = 2x

= \tt 1.3 = 2x - x

\color{plum} \hookrightarrow  \tt x = 1.3

Thus, the value of x = 1.3

Therefore :

▪︎The value of x = 1.3

<h2>=>> <u>Solution (Part B)</u> :</h2>

We know that :

▪︎The value of x = 1.3

Which means :

The length of the leg AM :

= \tt x + 1.4

= \tt 1.3 + 1.4

\color{plum} \tt leg \: AM= 2.7 \: inches

Thus, the length of the leg AM = 2.7 inches

The length of leg MG :

= \tt 2x + 0.1

=  \tt2 \times 1.3 + 0.1

= \tt 2.6 + 0.1

\color{plum} \tt\: leg \:MG = 2.7 \: inches

Thus, the length of the leg MG = 2.7 inches

Since the measure of the two legs are equal (2.7=2.7), we can conclude that we have found out the correct length of each leg.

Therefore :

▪︎Measure of leg AM = 2.7 inches

▪︎Measure of leg MG = 2.7 inches

<h2>=>> <u>Solution </u><u>(</u><u>part C</u><u>)</u> :</h2>

We know that :

Value of x = 1.3

Then, measure of the base AG :

=  \tt 3x - 0.4

= \tt 3 \times 1.3 - 0.4

= \tt 3.9 - 0.4

\color{plum}\tt \: Base  \: AG = 3.5 \:  inches

Thus, the measure of the base = 3.5 inches

Therefore :

▪︎ the length of base AG = 3.5 inches.

6 0
3 years ago
Which is an x-intercept of the continuous function in
arsen [322]
It’s (-1,0), because
5 0
2 years ago
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Solve the equation by Square Root Method 16n^2-25=0
Anton [14]

Answer:

Step-by-step explanation:

16n^2-25=0

16n^2=25

n^2=25/16

n=+-5/4

5 0
3 years ago
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The perimeter of a rectangle is 72 cm. The length is 3 more than twice the width What
solmaris [256]
<h3><u>Solution</u></h3>

<u>Given </u><u>:</u><u>-</u>

  • Perimeter of rectangle = 72 cm
  • The length is 3 more than twice the width.

<u>F</u><u>i</u><u>n</u><u>d</u><u> </u><u>:</u><u>-</u>

  • Dimensions of rectangle
<h3 /><h3><u>Explantion</u></h3>

<u>Using </u><u>Formula</u>

\boxed{\underline{\tt{\red{\:(perimeter_{rectang}\:=\:2\times (Length+Width)}}}}

<u>Let,</u>

  • Length of Rectangle = x cm
  • Breadth of Rectangle = y cm

<u>According</u><u> to</u><u> question</u><u>,</u>

==> perimeter of Rectangle = 72

==> 2(x+y) = 72

==> x + y = 72/2

==> x + y = 36_________________(1)

<u>Again,</u>

==> x = 2y + 3

==> x - 2y = 3__________________(2)

<u>Subtract</u><u> </u><u>equ(</u><u>1</u><u>)</u><u> </u><u>&</u><u> </u><u>equ(</u><u>2</u><u>)</u>

==> y + 2y = 36 - 3

==> 3y = 33

==> y = 33/3

==> y = 11

<u>keep </u><u>in </u><u>equ(</u><u>1</u><u>)</u>

==> x - 2×11 = 3

==> x = 3 + 22

==> x = 25

<h3><u>Hence</u></h3>

  • <u>Length</u><u> of</u><u> </u><u>Rectangle</u><u> </u><u>=</u><u> </u><u>2</u><u>5</u><u> </u><u>cm</u>
  • <u>Width </u><u>of </u><u>Rectangle</u><u> </u><u>=</u><u> </u><u>1</u><u>1</u><u> </u><u>cm</u>

<h3><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u></h3>

<h3 />

7 0
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A standard pie is 9 inches in diameter and 1 1/4 deep. What is the area of the top of the pie round to the nearest tenth at the
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The area would be 18 inches and you would need a ten by ten square to cover it.
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