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3 years ago

Help please!!! I don’t understand this question

Mathematics

1 answer:

Elenna [48]3 years ago

8 0

Answer:

Step-by-step explanation:

Let us first write an equation. Using the SOHCAHTOA rule, we should know that the tangent of an angle equals it's $\frac{opposite}{adjacent}$ . The opposite of our given 20° angle is 9, and the adjacent side is x.

$tan(20$ ° $)=\frac{9}{x}$

$0.364=\frac{9}{x} \\x=\frac{9}{0.364}\\x=24.7$

C

I hope this helps! Let me know if you have any questions :)

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Number 53

Solnce55 [7]

X-intercepts
f(x) = 0

4x² - 15x - 4 = 0

4x² - 16x + x - 4 = 0

4x(x - 4) + 1(x - 4) = 0

(x - 4)(4x + 1) = 0 ⇔ x - 4 = 0 or 4x + 1 = 0

x = 4 or 4x = - 1 ⇒ x = - 1/4

Answer: -1/4 and 4.

8 0

3 years ago

3x − 1/2(8x − 2) = 4 step 1: 3x − 4x 1 = 4 step 2: x 1 = 4 step 3: x 1 − 1 = 4 − 1 step 4: x = 3 which step was the error made a

Mrrafil [7]

3x-1/2(8x-2)=4
3x-4x+1=4
-x=3
X=-3

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3 years ago

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LenKa [72]

The answer would be 34, here is my work

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3 years ago

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Dafna1 [17]

Answer:

Step-by-step explanation:

6 0

3 years ago

Suppose that 1% of the employees of a certain company use illegal drugs. This company performs random drug tests that return pos

nikklg [1K]

Answer:

a) Pr(drug user| positive test) = 0.3333

b) The probability that he will failed his first test = 0.9703

c) the probability that he is a drug user since failed his second drug test

= 0.961165

Step-by-step explanation:

From the given information:

Suppose that 1% of the employees of a certain company use illegal drugs.

Probability of illegal drug user = 0.01

Probability of user that do not use drug = 1 - 0.01 = 0.99

From the person that is a illegal drug user, the company performs random drug tests that return positive results = 0.99

Therefore, the negative result for illegal drug user = 1 - 0.99 = 0.01

However, it also has a 2% false positive rate.

i.e the probability of the user that do not use drug has a positive result of 2% = 0.02

Thus, the probability of the user that do not use drug has a negative result of = 1 - 0.02

= 0.98

We are tasked to answer the following questions.

a) Steve, an employee at the company, has a positive test. What is the probability that he is a drug user?

i.e This employee we are taking about is a drug user and he has a positive test.

Thus;

Pr(drug user| positive test) = $\dfrac{0.99 \times 0.01}{0.99 \times 0.01+ 0.02 \times 0.99}$

Pr(drug user| positive test) = $\dfrac{0.0099}{0.0099+0.0198}$

Pr(drug user| positive test) = $\dfrac{0.0099}{0.0297}$

Pr(drug user| positive test) = 0.3333

b) Knowing he failed his first test, what is the probability that Steve will fail his next drug test?

The probability that he will failed his first test = ((0.01 × 0.01) + (0.99×0.98))

The probability that he will failed his first test = ( 1 × 10⁻⁴ + 0.9702)

The probability that he will failed his first test = 0.9703

c) Steve just failed his second drug test. Now, what is the probability that he is a drug user?

the probability that he is a drug user since he failed his second drug test using Bayes theorem can be expressed as:

= $\dfrac{0.01 \times(0.99\times 0.99)}{0.01 \times (0.99 \times0.99)+ 0.99(0.02 \times0.02)}$

the probability that he is a drug user since failed his second drug test

= $\dfrac{0.01 \times(0.9801)}{0.01 \times (0.9801)+ 0.99(4 \times 10^{-4})}$

the probability that he is a drug user since failed his second drug test

= $\dfrac{0.009801}{0.009801+ 3.96 \times 10^{-4}}$

the probability that he is a drug user since failed his second drug test

= 0.961165

6 0

3 years ago