Answer:
Marginal revenue = R'(Q) = -0.6 Q + 221
Average revenue = -0.3 Q + 221
Step-by-step explanation:
As per the question,
Functions associated with the demand function P= -0.3 Q + 221, where Q is the demand.
Now,
As we know that the,
Marginal revenue is the derivative of the revenue function, R(x), which is equals the number of items sold,
Therefore,
R(Q) = Q × ( -0.3Q + 221) = -0.3 Q² + 221 Q
∴ Marginal revenue = R'(Q) = -0.6 Q + 221
Now,
Average revenue (AR) is defined as the ratio of the total revenue by the number of units sold that is revenue per unit of output sold.
![Average\ revenue\ = \frac{Total\ revenue}{number\ of\ units\ sold}](https://tex.z-dn.net/?f=Average%5C%20revenue%5C%20%3D%20%5Cfrac%7BTotal%5C%20revenue%7D%7Bnumber%5C%20of%5C%20units%5C%20sold%7D)
Where Total Revenue (TR) equals quantity of output multiplied by price per unit.
TR = Price (P) × Total output (Q) = (-0.3Q + 221) × Q = -0.3 Q² + 221 Q
![Average\ revenue\ = \frac{TR}{Q}](https://tex.z-dn.net/?f=Average%5C%20revenue%5C%20%3D%20%5Cfrac%7BTR%7D%7BQ%7D)
![Average\ revenue\ = \frac{-0.3Q^{2}+221Q}{Q}](https://tex.z-dn.net/?f=Average%5C%20revenue%5C%20%3D%20%5Cfrac%7B-0.3Q%5E%7B2%7D%2B221Q%7D%7BQ%7D)
∴ Average revenue = -0.3Q + 221
Jerry worked 5 hours. Jaun worked 15 hours. Marcia worked 8 hours.
Answer:
g≤6
Step-by-step explanation: