All categories

4 years ago

Alycia cabbed 84 pints of strawberry jam.How many quarts of jam did alycia can

Mathematics

1 answer:

dmitriy555 [2]4 years ago

3 0

Answer:

Step-by-step explanation:

One pint is equal to 0.5 quarts. This means that in order to find how many quarts Alycia cans we need to divide the number of pints by 2.

84/2=42

Alycia cans 42 quarts.

You might be interested in

Olivia has c comic books. Jackie has 3 times as many comic books as Olivia. Write an

Nana76 [90]

Answer:

Step-by-step explanation:

Hope this helps!

Have a nice day :)

5 0

3 years ago

4 terms of this sequence

weeeeeb [17]

Answer:

5,8,13,20

Step-by-step explanation:

f(n)=n²+4

f(1)=1²+4=1+4=5

f(2)=2²+4=4+4=8

f(3)=3²+4=9+4=13

f(4)=4²+4=16+4=20

3 0

3 years ago

Read 2 more answers

How to find coordinates of a point using ratio

Marat540 [252]

m1=3, m2= 1

point A= (-5,4)

point B=(7,-2)

x=m1x2+m2x1/ m1+m2 , y=m1y2+m2y1 / m1+m2

x= 3×7 +1×-5/3+1 , y= 3×-2+1×4 / 3+1

x= 21-5/4, y= -6+4/4

x= 16/4, y= -2/4

x= 4, y= 0.5

5 0

3 years ago

What is an equation of the line that passes through the points (-1,-2) and (2,4)?

Aleks04 [339]

Y=2x is an equation that passes through those points

8 0

3 years ago

Read 2 more answers

Perform the indicated operation to write given polynomial in standard form: (2x^3 − 6x^2 − 7x − 2) +(x^3 +x^2 +6x − 12)

Kipish [7]

Answer:

$\left(2x^3-6x^2-7x-2\right)+\left(x^3+x^2+6x-12\right)=3x^3-5x^2-x-14$

Step-by-step explanation:

To add the polynomials

Remove parentheses:

$\left(2x^3-6x^2-7x-2\right)+\left(x^3+x^2+6x-12\right)=2x^3-6x^2-7x-2+x^3+x^2+6x-12$

Group like terms:

$=2x^3+x^3-6x^2+x^2-7x+6x-2-12$

Add similar elements:

$=3x^3-6x^2+x^2-7x+6x-2-12\\=3x^3-5x^2-7x+6x-2-12\\=3x^3-5x^2-x-2-12\\=3x^3-5x^2-x-14$

The Standard Form for writing down a polynomial is to put the terms with the highest degree first,its term of 2nd highest is 2nd etc..

In our case the standard form is

$\left(2x^3-6x^2-7x-2\right)+\left(x^3+x^2+6x-12\right)=3x^3-5x^2-x-14$

3 0

3 years ago