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allsm [11]
2 years ago
7

Please solve this problem

Mathematics
1 answer:
Debora [2.8K]2 years ago
5 0

Answer:

sorry i am not sure

Step-by-step explanation:

sorry i am not sure

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Solve for z. z−4/9−1/3=5/9
laila [671]
Z-4/9-1/3=5/9
z-4 =5/9(9-1/3)

z-4 =4.414814815

z =8.814
4 0
3 years ago
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Write the equation of the line that is perpendicular to the line 3x + y = 7 and passes through the point (6, -1).
ira [324]
Line:
3x+y=7
y=-3x+7

Slope of Perpendicular Line: 1/3x

For the perpendicular line to contain point (6,-1) the y-intercept would be (0,1), thus the equation of the line would be y=1/3x+1

y=1/3x+1

5 0
3 years ago
If the date of the second Thursday of the month is a perfect square, what is the date of the last Monday of the month?
Inga [223]

Answer:

last Monday is 27

Step-by-step explanation:

perfect square: 4, 9 , 16

2nd Thursday is a day >5 and < 14 day from the begining of the month, therefore the only day fit the criteria is 9th of the month.

last Monday is 27

Sun Mon Tue Wen Thu Fri Sat

                                  9     10  11

12    13      14     15     16     17  18

.........................................................

26    27

3 0
3 years ago
Choose all the lines that are parallel to the line pictured in the graph bellow.
viktelen [127]

Answer:

a. y = -½x

b. y = -½x + 3

c. 2y = -x - 4

e. x + 2y = 8

Step-by-step explanation:

Parallel lines have the same slope. Therefore, the lines that will be parallel to the given line on the graph would have the same slope as the line of the graph.

First, find the slope of the line on the graph:

m = \frac{y_2 - y_1}{x_2 - x_1}

Use the coordinates of any two points on the line. Let's use (-4, 0) and (0, -2)

m = \frac{-2 - 0}{0 -(-4)} = \frac{-2}{4} = -\frac{1}{2}

Slope of the line on the graph is -½.

Check each given line equation, ensure they are in the slope-intercept form and find out if the value of their slope is the same as -½.

Slope-intercept form is given as y = mx + b, where, m = slope.

Option 1: y = -½x

The slope of this line is -½, therefore it is parallel to the line on the graph.

Option 2: y = -½x + 3

The slope of this line is also -½, therefore it is parallel to the line on the graph.

Option 3: 2y = -x - 4

Rewrite in slope-intercept form.

y = -x/2 - 4/2

y = -½x - 2

The slope of this line is -½, therefore it is parallel to the line on the graph.

Option 4: y = 2x - 5.

The slope of this line is 2, therefore it is NOT parallel to the line on the graph.

Option 5: x + 2y = 8

Rewrite in slope-intercept form.

2y = 8 - x

y = 8/2 - x/2

y = 4 - ½x

The slope of this line is -½, therefore it is parallel to the line on the graph.

3 0
3 years ago
A has the coordinates (–4, 3) and B has the coordinates (4, 4). If DO,1/2(x, y) is a dilation of △ABC, what is true about the im
fomenos
A dilation is a transformation D_{o,k}(x,y), with center O and a scale factor of k that is not zero, that maps O to itself and any other point P to P'. The center O is a fixed point, P' is the image of P, points O, P and P' are on the same line.

In a dilation of D_{o, \frac{1}{2} }(x,y), the scale factor, \frac{1}{2} is mapping the original figure to the image in such a way that the distances from O to the vertices of the image are half the distances from O to the original figure. Also the size of the image is half the size of the original figure.

Therefore, <span>If D_{o, \frac{1}{2} }(x,y) is a dilation of △ABC, the truth about the image △A'B'C'</span> are:

<span>AB is parallel to A'B'.

D_{o, \frac{1}{2} }(x,y)=( \frac{1}{2}x,  \frac{1}{2}y)

The distance from A' to the origin is half the distance from A to the origin.</span>
3 0
4 years ago
Read 2 more answers
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