Answer:
Can I get more details on this question?
Step-by-step explanation:
If so, I can probably help you a little bit more. And I will edit my response
<u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u><u>:</u><u> </u>√15 units
Step-by-step explanation:
Let (6,1) be (x^1,y^1) and (1,-9) be (x^2,y^2) .
As we know ,
Distance(D) = √(x^1-x^2) +(y^1-y^2)
Now,
D= √(x^1-x^2) +(y^1-y^2)
= √(6-1) +(1+9)
= √5+10
= √15 units
: Therefore the distance between (6,1) and (1,-9) is √15 units.
Answer:
q. (3+t)=2-4t
q.3+q.t=2-4t
4t+q.t=2-3q
t (4+q)=2-3q
t=2-3q/4+q
Step-by-step explanation:
PLZZ MARK AS BRAINLIEST!!!!!
The plane starts at 202 m.
All altitudes are in meters.
After 1 second, it is at 202 - 1.8
After 2 seconds, it is at 202 - 1.8 * 2
After 3 seconds, it is at 202 - 1.8 * 3
etc.
After x seconds, it is at 202 - 1.8 * x
202 - 1.8 * x is the same as 202 - 1.8x
Answer: F. t(x) = 202 - 1.8x