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PilotLPTM [1.2K]
3 years ago
5

Use the correct math operation to determine the unit price (price per ounce) for the 2-liter bottle priced at $1.39. (67.6 ounce

s)
Mathematics
2 answers:
ser-zykov [4K]3 years ago
5 0

Answer:

The correct math operation to determine the unit price is division

Step-by-step explanation:

In 2-liter bottle of water:

67.6 ounces cost $1.39, then

=> 1 ounce costs

\$1.39\div 67.6\approx \$0.0205

dsp733 years ago
4 0

Well to find this answer, you want to divide $1.39 by 67.6. When you do this you get 0.0205. This is roughly 2 cents per ounce.

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The approximate time between two high tides or<br> two low tides is?
NeX [460]

Answer:

It's (very roughly) 12 hours from one high tide to the next, and of course the same for low tides. That's because the tides produced when the Moon is directly overhead or in the opposite direction are the same. Same with two low tides, since there are two tides a day (both low and high).

5 0
3 years ago
Read 2 more answers
About 7% of the population has a particular genetic mutation. 400 people are randomly selected. Find the standard deviation for
Deffense [45]

Answer:

5.10 people

Step-by-step explanation:

Calculation to Find the standard deviation for the number of people with the genetic mutation

Using this formula

Standard deviation = √ ( n * p * q)

Where,

n = 400

p = .07

q = 100%-7% = 93% or .93

Let plug in the formula

Standard deviation =√400*07*.93

Standard deviation =√26.04

Standard deviation = 5.10 people

Therefore the standard deviation for the number of people with the genetic mutation is 5.10 people.

5 0
3 years ago
I'm really bad at math
Lynna [10]
What chapter is this?

6 0
3 years ago
I need help on this 6th grade math problem
vivado [14]

Answer: x<17.5

Step-by-step explanation:

Subtract  from both sides: x+2.5-2.5<20-2.5

Simplify the arithmetic: x<20-2.5

Simplify the arithmetic: x<17.5

Hope it helps!

4 0
2 years ago
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How many integers between 10000 and 99999, inclusive, are divisible by 3 or<br> 5 or 7?
Yuki888 [10]

Answer: Hence, there are approximately 48884 integers are divisible by 3 or 5 or 7.

Step-by-step explanation:

Since we have given that

Integers between 10000 and 99999 = 99999-10000+1=90000

n( divisible by 3) = \dfrac{90000}{3}=30000

n( divisible by 5) = \dfrac{90000}{5}=18000

n( divisible by 7) = \dfrac{90000}{7}=12857.14

n( divisible by 3 and 5) = n(3∩5)=\dfrac{90000}{15}=6000

n( divisible by 5 and 7) = n(5∩7) = \dfrac{90000}{35}=2571.42

n( divisible by 3 and 7) = n(3∩7) = \dfrac{90000}{21}=4285.71

n( divisible by 3,5 and 7) = n(3∩5∩7) = \dfrac{90000}{105}=857.14

As we know the formula,

n(3∪5∪7)=n(3)+n(5)+n(7)-n(3∩5)-n(5∩7)-n(3∩7)+n(3∩5∩7)

=30000+18000+12857.14-6000-2571.42-4258.71+857.14\\\\=48884.15

Hence, there are approximately 48884 integers are divisible by 3 or 5 or 7.

5 0
4 years ago
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