How do you write 6.0000 as a percentage

Suppose that A is the price of an Apple stock and M is the price of a Microsoft stock. Consider the following statement: Apple h

stira [4]

Answer:

The random variables in this situation are the stock prices A and M.

The mean of Apple's stock prices is greater than the mean of Microsoft's stock prices.

The standard deviation of the price of Microsoft shares is smaller than that of Apple's share prices.

Step-by-step explanation:

The random variables in this situation are the stock prices A and M.

According to the text, it is stated that the values of Apple shares are usually higher than those of Microsoft shares. This implies that, since they are random variables, the mean of Apple's stock prices is greater than the mean of Microsoft's stock prices.

In stock prices, the standard deviation is a measure of the risk or stability of a share price. It is a measure of the price variation around its average value. The more stable the value of an action, the smaller the value of the standard deviation.

Then, according to the text, we can affirm that, since Microsoft's prices are more stable, the standard deviation of the price of Microsoft shares must be less than that of Apple's share prices.

7 0

3 years ago

Give the solutions to 23 + √36

Alenkinab [10]

Answer: 29

Step-by-step explanation:

23 + √36

Square root of 36 means two same numbers that will give you 36 when multiplied which is 6

23 + √36

= 23+6

= 29

3 0

3 years ago

Read 2 more answers

Use the graph of △ABC with midsegments DE, EF and DF. Show that EF is parallel to AC and that EF=1/2 AC

Vinvika [58]

According to the midsegment theorem, the midsegments are parallel to

and half the length of the opposite side.

The completed statement are as follows;

Because the slopes of $\overline{EF}$ and $\overline{AC}$ are both -4, $\overline{EF}$ ║ $\overline{AC}$

EF = $\underline{\sqrt{17}}$ and AC = $\underline{2 \cdot \sqrt{17} }$

Because $\underline{\sqrt{17} }$ = $\underline{\frac{1}{2} \cdot 2 \cdot \sqrt{17} }$ , $EF = \frac{1}{2} \cdot AC$

Reasons:

From the given graph of ΔABC, we have;

Coordinates of the points A, B, and C are; A(-5, 2), B(1, -2), and C(-3, -6)

The coordinates of the point D and E on $\mathbf{\overline{DE}}$ are; D(-4, -2), and E(-2, 0)

The coordinates of the point F is; F(-1, -4)

$Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$\displaystyle Slope \ of \ line \ \overline{AC} = \mathbf{\frac{(-6) - 2}{-3 - (-5)} = \frac{-8}{2}} = -4$

$\displaystyle Slope \ of \ line \ \overline{EF} = \frac{0 - (-4)}{-2 - (-1)} = \frac{4}{-1} = -4$

$Length \ of \ segment,\ l = \sqrt{\left (x_{2}-x_{1} \right )^{2}+\left (y_{2}-y_{1} \right )^{2}}$

Length of EF = √((-1 - (-2))² + (-4 - 0)²) = √(17)

Length of AC = √((-3 - (-5))² + (-6 - 2)²) = √(4 × 17) = 2·√(17)

Therefore, we have;

Because the slope of $\mathbf{\overline {EF}}$ and $\mathbf{\overline {AC}}$ are both , -4, $\overline {EF}$ ║ $\overline {AC}$ . EF = $\underline{\sqrt{17}}$ , and AC

= $\underline{\frac{1}{2} \cdot 2 \cdot \sqrt{17}}$ ,. Because $\underline{\sqrt{17}}$ = $\underline{\frac{1}{2} \cdot 2 \cdot \sqrt{17}}$ , $EF =\mathbf{ \frac{1}{2} AC}$