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Elina [12.6K]
3 years ago
6

Dose anyone know the answer to this question?

Mathematics
2 answers:
natima [27]3 years ago
8 0

Answer:

\boxed{\sf -3}

Step-by-step explanation:

The denominators are same. Add fractions.

\displaystyle \sf \frac{-3k+6}{k-2}

Factor out the expression in the numerator.

\displaystyle \sf \frac{-3(k-2)}{k-2}

Cancel common terms.

\displaystyle \sf \frac{-3}{1}=-3

RideAnS [48]3 years ago
4 0

Answer:

-3

Step-by-step explanation:

-3k / ( k-2)   + 6 / ( k-2)

since the denominators are the same we can add the numerators

(-3k+6) / ( k-2)

Factor out -3

-3 ( k-2)/ ( k-2)

Cancel like terms

-3

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Tiger cubs are around 2 years old when they leave their mothers. In the wild, tigers live about 11 years. About what percent of
pogonyaev

Answer:

18.18%

Step-by-step explanation:

Cross-multiply

11 years ------------ 100% of life

2 years ------------- x% of life

11/2 = 100/x ===> 11x = 2*100 ===> 11x = 200 ===> x = 200/11 ===> x = 18.18%

5 0
3 years ago
Solve for b in the literal equation y = 11x + 11b
bekas [8.4K]

Answer:

<h2>b = y/11  -x </h2>

Step-by-step explanation:

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7 0
3 years ago
Read 2 more answers
Can someone help me please? It’s like my 3rd time trying to get some answers for this question. Thanks. :)
mote1985 [20]

Answer:

both rates of change equal the slope of the line (3/4)

Step-by-step explanation:

Part a)

We calculate the rate of change using the formula:

\frac{y_2-y_1}{x_2-x_1}

for the first interval [0,6], we calculate the y-values at x=0 and x=6;

at x=0 : y=\frac{3}{2} (0)+2=2

at x=6 : y=\frac{3}{2} (6)+2=11

therefore, the rate of change in this interval is: \frac{y_2-y_1}{x_2-x_1}=\frac{11-2}{6-0}=\frac{9}{6} =\frac{3}{2}

For the second interval [-4,4], we calculate the y-values at x=-4 and x=4;

at x=-4 : y=\frac{3}{2} (-4)+2=-4

at x=4 : y=\frac{3}{2} (4)+2=8

therefore, the rate of change in this interval is: \frac{y_2-y_1}{x_2-x_1}=\frac{8-(-4)}{4-(-4)}=\frac{12}{8} =\frac{3}{2}

Part b):

Notice that both rates of change equal the value of the slope of the linear function (3/2)

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