What is half of 5 3/4?

The height h in feet of a ball thrown vertically upward from the top of a 288-foot tall building is given by h=288+48t-16t^2 whe

mr Goodwill [35]

6 sec can take penny to strike the ground.

Solution:

Given data:

$H_0=288$ feet

$V_0=48$ feet

$h(t)=288+48t-16t^2$

Re-arrange the terms from greatest degree to smallest degree.

$h(t)=-16t^2+48t+288$

We can solve it by applying quadratic formula,

$$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Here a = –16, b = 48, c = 288

$$t=\frac{-48\pm \sqrt{48^2-4(-16)(288)}}{2(-16)}$

$$t=\frac{-48\pm \sqrt{2304+18432}}{-32}$

$$t=\frac{-48\pm \sqrt{20736}}{-32}$

$$t=\frac{-48\pm144}{-32}$

Now, write find two t's using plus and minus operation.

$$t=\frac{-48+144}{-32},\ \ t=\frac{-48-144}{-32}$

$$t=\frac{96}{-32},\ \ t=\frac{-192}{-32}$

t = –3 (or) t = 6

We cannot write time is negative. so neglect t = –3.

Therefore t = 6.

Hence 6 sec can take penny to strike the ground.

8 0

2 years ago

PLEASE HELP ITS DUE TODAYYY

Bumek [7]

Answer:

(-3,10) (0,5) (3,0) (6,-5)

Step-by-step explanation:

x intercept = 3

y intercept =5

If brainiest is earned its greatly appreciated

6 0

3 years ago

A company surveyed 2,600 North American airline passengers and reported that approximately 75% said that they carry a smartphone

geniusboy [140]

The probability that exactly six out of ten carry a smartphone when travelling is; P(6) = 0.146

The missing part of the question is;

The probability distribution of x is the binomial distribution with n = 10 and p = 0.75.

Calculate P(6)

This is a binomial probability distribution problem that has a general formula as; P(x) = ⁿCₓ × pˣ × q⁽ⁿ ⁻ ˣ⁾

Where;

p is probability of success

q is probability of failure

n is number of experiments

In this question;

n = 10

p = 75% = 0.75

q = 1 - p

q = 1 - 0.75

q = 0.25

Since six passengers are randomly selected, then applying the formula earlier quoted, we have;

P(6) = ¹⁰C₆ × 0.75⁶ × 0.25⁽¹⁰ ⁻ ⁶⁾

P(6) = 0.146

Read more at; brainly.com/question/24239758

4 0

2 years ago

Evaluate the integral e^xy w region d xy=1, xy=4, x/y=1, x/y=2

LUCKY_DIMON [66]

Make a change of coordinates:

$u(x,y)=xy$
$v(x,y)=\dfrac xy$

The Jacobian for this transformation is

$\mathbf J=\begin{bmatrix}\dfrac{\partial u}{\partial x}&\dfrac{\partial v}{\partial x}\\\\\dfrac{\partial u}{\partial y}&\dfrac{\partial v}{\partial y}\end{bmatrix}=\begin{bmatrix}y&x\\\\\dfrac1y&-\dfrac x{y^2}\end{bmatrix}$

and has a determinant of

$\det\mathbf J=-\dfrac{2x}y$

Note that we need to use the Jacobian in the other direction; that is, we've computed

$\mathbf J=\dfrac{\partial(u,v)}{\partial(x,y)}$

but we need the Jacobian determinant for the reverse transformation (from $(x,y)$ to $(u,v)$ . To do this, notice that

$\dfrac{\partial(x,y)}{\partial(u,v)}=\dfrac1{\dfrac{\partial(u,v)}{\partial(x,y)}}=\dfrac1{\mathbf J}$

we need to take the reciprocal of the Jacobian above.

The integral then changes to

$\displaystyle\iint_{\mathcal W_{(x,y)}}e^{xy}\,\mathrm dx\,\mathrm dy=\iint_{\mathcal W_{(u,v)}}\dfrac{e^u}{|\det\mathbf J|}\,\mathrm du\,\mathrm dv$
$=\displaystyle\frac12\int_{v=}^{v=}\int_{u=}^{u=}\frac{e^u}v\,\mathrm du\,\mathrm dv=\frac{(e^4-e)\ln2}2$

8 0

3 years ago

Alguém sabe como faz essas duas questões ?

joja [24]

Minha resposta: não.

7 0

3 years ago