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OLEGan [10]
2 years ago
6

Tiger cubs are around 2 years old when they leave their mothers. In the wild, tigers live about 11 years. About what percent of

their lives do tigers spend with their mothers
Mathematics
1 answer:
pogonyaev2 years ago
5 0

Answer:

18.18%

Step-by-step explanation:

Cross-multiply

11 years ------------ 100% of life

2 years ------------- x% of life

11/2 = 100/x ===> 11x = 2*100 ===> 11x = 200 ===> x = 200/11 ===> x = 18.18%

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Step-by-step explanation:

4x - 3 + 5 = 2x + 7 - 8x

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           10x = 5

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Amira is solving the equation x2 – 6x = 1. Which value must be added to both sides of the equation to make the left side a perfe
likoan [24]
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3 years ago
Read 2 more answers
Brass is made from a mixture of copper and other elements. a mixture that is 80% copper is combined with a mixture that is 60% c
algol [13]

The equation that can be used to find x, the amount of the 60% mixture used to create the 65% mixture is:

0.60*x + 0.80*(100 - x) = 0.65*(100).    

<h3>Which equation we should use?</h3>

First, let's define two variables:

  • x = pounds of the 60% copper brass.
  • y = pounds of the 80% copper brass.

We know that we want to make 100 lb of 65% copper brass, then we must have that:

x + y = 100

And the percentage of copper before and after mixing must be the same, so we can write:

0.60*x + 0.80*y = 0.65*(x + y).

(where the percentages are written in decimal form).

Then we have a system of equations:

x + y = 100

0.60*x + 0.80*y = 0.65*(x + y).

To get a single equation, we can isolate the variable "y" on the first equation:

y = 100 - x

Now we replace that in the other equation:

0.60*x + 0.80*(100 - x) = 0.65*(100).      

This is what we wanted to get, an equation that can be used to find x, the amount of the 60% mixture used to create the 65% mixture.

If you want to learn more about systems of equations:

brainly.com/question/13729904

#SPJ1

4 0
2 years ago
Please help with the question on the picture!
ludmilkaskok [199]

Answer: B I think :)

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2 years ago
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